“二等分法”运行无限次

Question

我编写了一个“二等分方法”，但是它可以永远运行，请帮助我，非常感谢 我的代码只是找到x ^ 3 + 4 * x ^ 2-10的最接近根的简单方法，认为它将停止14次，但不是（我尝试将a和b设置为1和2）

 void bis(double a, double b)
{
    cout << fixed << setprecision(8);
    double x = (a + b) / 2;
    double result = pow(x, 3) + 4 * pow(x, 2) - 10;
    int n = 0;
    while (abs(result) > 0,0001) {
        x = (a + b) / 2;
        result = pow(x, 3) + 4 * pow(x, 2) - 10;
        if (pow(a, 3) + 4 * pow(a, 2) - 10 > 0 && pow(b, 3) + 4 * pow(b, 2) - 10 < 0) {
            n++;
            if (result > 0) {
                cout << n << "     " << a << "    " << b << "   " << x << "    " << result << endl;
                a = x;
            } else if (result < 0) {
                cout << n << "     " << a << "    " << b << "   " << x << "    " << result << endl;
                b = x;
            }
        }
        if (pow(a, 3) + 4 * pow(a, 2) - 10 < 0 && pow(b, 3) + 4 * pow(b, 2) - 10 > 0) {
            n++;
            if (result > 0) {
                cout << n << "     " << a << "    " << b << "   " << x << "    " << result << endl;
                b = x;
            } else if (result < 0) {
                cout << n << "     " << a << "    " << b << "   " << x << "    " << result << endl;
                a = x;
            }
        }
    }
}