Question

我有如下数据：字段值

0   CRD 146099
1   LegalName   CHUNG, BUCK CHWEE
2   BusName PRINCIPA FINANCIAL ADVISORS
3   URL https://adviserinfo.sec.gov/IAPD/content/ViewF...
4   CRD 170701
5   LegalName   MESSINA AND ASSOCIATES, INC
6   BusName FINANCIAL RESOURCES GROUP
7   URL https://adviserinfo.sec.gov/IAPD/content/ViewF...
8   CRD 133630
9   LegalName   ALAN EDELMAN
10  BusName EDELMAN, ALAN
11  URL https://adviserinfo.sec.gov/IAPD/content/ViewF...
12  CRD 131792
13  LegalName   RESOURCE MANAGEMENT LLC
14  BusName RESOURCE MANAGEMENT LLC
15  URL https://adviserinfo.sec.gov/IAPD/content/ViewF...

如何将其转换为CRD，LegalName，BusName，URL为列。我尝试使用pd.melt，但这似乎不是我想要的。

Answer 1

首先将split用于2列，然后通过cumcount创建计数器Series，通过set_index创建MultiIndex并通过unstack重塑形状：

df[['Field','Value']] = df['Value'].str.split(n=1, expand=True)

groups = df.groupby('Field').cumcount()
df = df.set_index([groups, 'Field'])['Value'].unstack()
print (df)
Field                      BusName     CRD                    LegalName  \
0      PRINCIPA FINANCIAL ADVISORS  146099            CHUNG, BUCK CHWEE   
1        FINANCIAL RESOURCES GROUP  170701  MESSINA AND ASSOCIATES, INC   
2                    EDELMAN, ALAN  133630                 ALAN EDELMAN   
3          RESOURCE MANAGEMENT LLC  131792      RESOURCE MANAGEMENT LLC   

Field                                                URL  
0      https://adviserinfo.sec.gov/IAPD/content/ViewF...  
1      https://adviserinfo.sec.gov/IAPD/content/ViewF...  
2      https://adviserinfo.sec.gov/IAPD/content/ViewF...  
3      https://adviserinfo.sec.gov/IAPD/content/ViewF...

Answer 2

我认为您正在寻找DataFrame。transpose

将大熊猫中的行数据转换为列数据

2 个答案: