总和而不计算重复值SQL

Question

我有一个表suivis，其中包含id_action和id_individu列，该表可以包含多个重复值（不是整个行，只有该列）。

示例：     

我还有一个表individus，其中包含一列statut_collaborateur，该表可以具有两个值：'no'和'granted'。

我需要帮助来计算statut_collaborateur =否和statut_collaborateur =授予但仅一次的id_individu的数量。

现在，我设法做到了：

SELECT  j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
        SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne, 
        SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe, 
        r.nom_responsable 
FROM individus AS i 
    LEFT JOIN suivis AS s ON s.id_individu = i.id_individu 
    LEFT JOIN jurys AS j ON j.id_jury = s.id_jury 
    LEFT JOIN societes AS so ON so.id_societe = j.id_societe 
    LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable 
WHERE s.id_action = 22 
AND j.statut IN (1,3) 
AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59' 
GROUP BY s.id_jury`

主要问题是我必须总和，我也尝试过计数，但结果相同，我的计数是5，应该是3（3个独立的individu）。

Answer 1

选择的列数应包含在分组依据

SELECT  j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
        SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne, 
        SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe, 
        r.nom_responsable 
FROM individus AS i 
    LEFT JOIN suivis AS s ON s.id_individu = i.id_individu 
    LEFT JOIN jurys AS j ON j.id_jury = s.id_jury 
    LEFT JOIN societes AS so ON so.id_societe = j.id_societe 
    LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable 
WHERE s.id_action = 22 
AND j.statut IN (1,3) 
AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59' 
GROUP BY j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,r.nom_responsable

Answer 2

仅使用表individus的不同语句加入所需的列

 SELECT  j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,
                SUM(CASE WHEN (i.statut_collaborateur = 'granted') THEN 1 ELSE 0 END) AS interne, 
                SUM(CASE WHEN (i.statut_collaborateur = 'no') THEN 1 ELSE 0 END) AS externe, 
                r.nom_responsable 
        FROM (SELECT DISTINCT i.id_individu ,i.statut_collaborateur from individus )AS i 
            LEFT JOIN suivis AS s ON s.id_individu = i.id_individu 
            LEFT JOIN jurys AS j ON j.id_jury = s.id_jury 
            LEFT JOIN societes AS so ON so.id_societe = j.id_societe 
            LEFT JOIN responsables AS r ON r.id_responsable = j.id_responsable 
        WHERE s.id_action = 22 
        AND j.statut IN (1,3) 
        AND j.date_debut BETWEEN '2018-01-01 00:00:00' AND '2018-10-23 23:59:59' 
GROUP BY j.date_debut, j.date_fin, j.titre, so.id_identite, so.nom_societe,r.nom_responsable