Question

我一直试图做很多sql操作只是为了得到理想的结果，但两天之后仍然没有快乐......

我有下面的SQL结果，并且正在尝试实现＆＃34;期望的结果＆＃34;表。它的作用是根据Stype per Branch总结NoScan的值。

Code    Branch  NoScan  sType
PK001   BF      258     R
PK001   BF      474     N
BO001   BF      435     N
MM006   BF      62      R
LH001   CP      2       F
RK001   CP      1       O
QB001   CP      26      N
TJ001   CP      3       F
GS147   DU      79      O
HR001   DU      5       F
IV002   DU      3       F
NP123   DU      149     O
WC001   EL      30      R
CO100   EL      230     R
CO100   EL      4       F


Desired Result

Branch      F(Count)        R(Count)        N(Count)        O(Count)
BF          0               320             909             0
CP          5               0               26              1
DU          8               0               0               228
EL          435             260             0               0

这是我的基本查询，但我没有包括我提出的其他查询，因为他们无论如何都无法获得所需的结果。

    ;with deli as 
    (
        SELECT  
                c.Code as Code
                ,dh.Branch as Branch
                ,COUNT(dh.dID) as NoScan
                ,dh.sType as sType
        FROM dbo.tblSDHead dh with (nolock)
            inner join dbo.tblCor c with (nolock) on dh.dID = c.code
            inner join dbo.tblSPD spd with(nolock) on dh.wbno = spd.wbno
        WHERE 
                dh.Branch IN 
                (
                    SELECT DISTINCT code
                    FROM tblloc
                    WHERE coid IN ('1','2')
                )
            and c.isactive = 1
            and c.sshd = 1
            and spd.pddate >= @startdate
            and spd.pddate < @enddate
            and spd.delicomp = 'Y'
            and dh.sType in ('N','O','R','F')
        GROUP BY 
            c.Code
            ,dh.branch
            ,dh.sType
    )
select 
    *
from
    (
        select 
            o.Code
            ,o.Branch
            ,o.NoScan
            ,o.sType
        from
            deli o
    ) overall
order by overall.branch asc

非常感谢任何帮助！感谢

Answer 1

使用case表达式进行条件聚合：

select branch,
       sum(case when sType = 'F' then NoScan else 0 end) as Fcount,
       sum(case when sType = 'N' then NoScan else 0 end) as Ncount,
       sum(case when sType = 'R' then NoScan else 0 end) as Rcount,
       sum(case when sType = 'O' then NoScan else 0 end) as Ocount
from tablename
group by branch

将tablename替换为生成输入的子查询（派生表）。

Answer 2

使用条件聚合，跳过cte：

select  
    Branch  = dh.Branch
  , F_Count = sum(case when left(dh.sType,1) = 'F' then 1 else 0 end)
  , R_Count = sum(case when left(dh.sType,1) = 'R' then 1 else 0 end)
  , N_Count = sum(case when left(dh.sType,1) = 'N' then 1 else 0 end)
  , O_Count = sum(case when left(dh.sType,1) = 'O' then 1 else 0 end)
  , NoScan  = count(dh.did)
  , sType   = dh.sType
from dbo.tblsdhead dh with (nolock)
    inner join dbo.tblCor c with (nolock) 
      on dh.did = c.code
    inner join dbo.tblspd spd with(nolock) 
      on dh.wbno = spd.wbno
where dh.Branch in (
    select distinct code
    from tblloc
    where coid in ('1','2')
    )
    and c.isactive = 1
    and c.sshd = 1
    and spd.pddate >= @startdate
    and spd.pddate < @enddate
    and spd.delicomp = 'Y'
    and dh.sType in ('ndx','onx','rdf','fdxe')
group by dh.branch

Answer 3

总体而言，您还需要再查询一次。

with deli as 
    (
        SELECT  
                c.Code as Code
                ,dh.Branch as Branch
                ,COUNT(dh.dID) as NoScan
                ,dh.sType as sType
        FROM dbo.tblSDHead dh with (nolock)
            inner join dbo.tblCor c with (nolock) on dh.dID = c.code
            inner join dbo.tblSPD spd with(nolock) on dh.wbno = spd.wbno
        WHERE 
                dh.Branch IN 
                (
                    SELECT DISTINCT code
                    FROM tblloc
                    WHERE coid IN ('1','2')
                )
            and c.isactive = 1
            and c.sshd = 1
            and spd.pddate >= @startdate
            and spd.pddate < @enddate
            and spd.delicomp = 'Y'
            and dh.sType in ('NDX','ONX','RDF','FDXE')
        GROUP BY 
            c.Code
            ,dh.branch
            ,dh.sType
    )
,overall as
    (
        select 
            o.Code
            ,o.Branch
            ,o.NoScan
            ,o.sType
        from
            deli o
    ) 
select o.Branch
      ,sum(case when o.sType = 'F' then o.NoScan else null end) as F_Count
      ,sum(case when o.sType = 'R' then o.NoScan else null end) as R_Count
      ,sum(case when o.sType = 'N' then o.NoScan else null end) as N_Count
      ,sum(case when o.sType = 'O' then o.NoScan else null end) as O_Count
from overall o
group by o.Branch

Answer 4

这似乎是一种错误的做法。如果您的sType列中有超过4个值，则需要更新查询。应该在表示层处理显示。

您应该尝试使用固定数量的列显示相同的结果，如下所示：

select branch, sType, sum(NoScan)
from table
group by branch, sType

sum的SQL结果显示重复的列值

4 个答案: