Question

我正在尝试对其中两行具有重复值的行的值求和，我的表格如下：

表名（客户）

value   years   total
1           30    30
3           10    10
4           15    15
4           25    25

我希望最终能够：

value  years   total
1      30      30
3      10      10
4      40      40

我尝试使用SELECT DISTINCT和GROUP BY来删除重复的行，也不需要在下面的代码中加入。无论这两个命令都无济于事。这也是我的代码：

SELECT DISTINCT 
  value,
  years,
  SUM(customer.years) AS total 
FROM customer 
INNER JOIN language 
  ON customer.expert=language.l_id 
GROUP BY 
  expert, 
  years;

但是这产生了第一个表的副本，任何输入欢迎。感谢!!!

Answer 1

SELECT
   value,
   SUM(years) AS years,
   SUM(total) AS total
FROM customers
GROUP BY value;

您想要年份的总和以及每个按 - 值分组的总和的总和。

Answer 2

SELECT 
  value,
  years,
  SUM(customer.years) AS total FROM (SELECT DISTINCT 
  value,
  years,
  customer.years AS total 
FROM customer 
INNER JOIN language 
  ON customer.expert=language.l_id ) as TABLECUS
GROUP BY 
  expert, 
  years;

对重复的行值求和

2 个答案: