我正在使用Oracle SQL数据库。 我正在尝试将这2个查询合并到同一张表中的一个查询中:
select count(CustomerID) from Customers
where (City = 'Berlin' or City = 'London')
from Customers;
select count(CustomerID) from Customers
where (City = 'Mannheim' or City = 'Strasbourg')
from Customers;
我的输出想像是在2列上导出的内容:
| Berlin & London | Mannheim & Strasbourg |
|-----------------------------------------|
| 5 | 10 |
此处为db的示例,https://www.w3schools.com/sql/trysql.asp?filename=trysql_op_in
我认为答案将是:
(select count(CustomerID) from Customers
where (City = 'Berlin' or City = 'London'))
union
(select count(CustomerID) from Customers
where (City = 'Marseille' or City = 'Tsawassen'));
union
(select count(CustomerID) from Customers
where (City = 'Strasbourg' or City = 'Madrid'));
仍在测试...
最后通过这种情况完成了工作。 感谢所有参与的人!
SELECT
COUNT(CASE
WHEN work_zone = 'AMBGI01' OR
work_zone = 'AMBGI02' OR
work_zone = 'AMBGI03' AND
task_type = 'P' THEN work_zone
END) "HighBay Putaways",
COUNT(CASE
WHEN work_zone = 'AMBGI04' OR
work_zone = 'AMBGI05' OR
work_zone = 'AMBGI06' OR
work_zone = 'AMBGI07' AND
task_type = 'P' THEN work_zone
END) "LowBay Putaways",
COUNT(CASE
WHEN from_loc_id = 'THEWALL' AND
task_type = 'P' THEN from_loc_id
END) "THE WALL",
COUNT(CASE
WHEN tag_id like '%' AND
from_loc_id like 'EXPANS%' AND
task_type = 'P' THEN tag_id
END) "EXPANSION",
COUNT(CASE
WHEN final_loc_id like '_______' AND
(status = 'In Progress' OR
status = 'Released') AND
task_type = 'R' THEN final_loc_id
END) "Replens"
FROM move_task;
答案 0 :(得分:2)
不清楚您有两个表(join
,select j.*, a.pass
from july j join
august a
on j.account = a.account
where (j.pass = 'yes' and a.pass = 'no') or
(j.pass = 'no' and a.pass = 'yes');
)还是一个。如果有两个,则需要向我们展示结构。 w3schools.com说没有像customers
这样的表,并且country
不包含country
列。无论如何,您都需要有条件的customers
,如下所示:
store
您也可以使用count
,但这更简单,更易读,并且可以在较早的Oracle版本中使用。
答案 1 :(得分:1)
最简单的方法如下:
select count(CASE WHEN City = 'Berlin' or City = 'London' THEN City END) "Berlin & London"
, count(CASE WHEN City = 'Mannheim' or City = 'Strasbourg' THEN City END) "Mannheim & Strasbourg"
from Customers