Question

我正在尝试创建一个查询，它将为我提供打开的门票数量＆amp;在按周分组的指定时间范围内关闭。有没有人有关于如何实现这一目标的想法？

如果我从T1.closed而不是T1.opened更改时间参考，我会为一列而不是另一列进行正确的分组。

以下是我到目前为止的情况。

SELECT 
FROM_DAYS(TO_DAYS(T1.created) -MOD(TO_DAYS(T1.created) -1, 7)) as week,
COUNT(T1.created) as Opened, COUNT(T2.ticket) as Closed

FROM issues as T1
LEFT JOIN issues T2 on T1.ticket = T2.ticket AND T1.closed 
BETWEEN (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) 
AND (DATE_SUB(CURDATE(), INTERVAL 1 MONTH)) AND T1.closed IS NOT NULL

WHERE
T1.created > (DATE_SUB(CURDATE(), INTERVAL 2 MONTH))
AND
T1.created < (DATE_SUB(CURDATE(), INTERVAL 1 MONTH))

GROUP BY
week

Answer 1

据我所知t1.opened和t1.closed是日期，所以你可以选择：

select `week`, sum(`opened`), sum(`closed`) from
(
    select week(t1.opened) as `week`, count(*) as `opened`, 0 as `closed`
    from issues as t1
    where t1.opened is not null AND ##FILTER BY OPENED##
    group by week(t1.opened)
union all
    select week(t2.closed) as `week`, 0 as `opened`, count(*) as `closed`
    from issues as t2
    where t2.closed is not null AND ##FILTER BY CLOSED##
    group by week(t2.closed)
) as t3
group by `week`

注意：您看到有2个查询，请不要加入，因为可能有数周没有关闭/打开的问题

注意2：如果你想按创建日期添加过滤器 - 你需要考虑它应该如何工作，例如问题是在1月1日创建的，1月8日开放，1月15日关闭，应该生成以下每个范围： 1-7,2-8,9-16？

合并来自同一个表的2个MYSQL计数查询

1 个答案: