Question

我有一个Oracle表，其中包含多个活动的每日计数。我需要创建一个查询，显示一个月的每日活动和上一年的同一个月的总和。所以我最终会得到6个这样的列：

我创建了这两个SQL查询，这个查询提供了有关输入的日期参数的信息：

select extract(year from activitydate) as yr, extract(MONTH from 
activitydate) as mon, Sum(dicalls)
from updstats
Where ACTIVITYDATE BETWEEN TO_DATE (:STARTDATE,'MM/DD/YYYY') AND 
TO_DATE(:ENDDATE,'MM/DD/YYYY')
GROUP BY extract(year from activitydate), extract(MONTH from activitydate)
order by yr, mon

，这个提供上一个日期范围的数据：

select extract(year from activitydate) as Pyr, extract(MONTH from 
activitydate) as Pmon, Sum(dicalls)
from updstats
Where ACTIVITYDATE BETWEEN add_months(TO_DATE (:STARTDATE,'MM/DD/YYYY'),-12) 
AND add_months(TO_DATE(:ENDDATE,'MM/DD/YYYY'),-12)
GROUP BY extract(year from activitydate), extract(MONTH from activitydate)
order by Pyr, Pmon

我陷入困境，无法弄清楚如何将这两个结合起来给我提供我需要的数据集。

Answer 1

获取每月和每年的dicalls总和，并使用lag获取上一年同月的值。使用where子句筛选外部查询中的日期范围。（此查询输出表中的所有月份和年份。）

select yr,mth,dicalls
,lag(yr) over(partition by mth order by yr) prev_yr
,lag(mth) over(partition by mth order by yr) prev_mth
,lag(dicalls) over(partition by mth order by yr) prev_dicalls
from (select sum(dicalls) as dicalls,extract(month from activitydate) as mth,extract(year from activitydate) as yr
      from updstats
      group by extract(month from activitydate),extract(year from activitydate)
     ) x
order by 1,2

Answer 2

您可以将这两个查询作为带有rownumber的子查询加入。

 select * from 
            (select extract(year from activitydate) as yr, 
            extract(MONTH from activitydate) as mon, 
            Sum(dicalls),
           row_number() over(partition by extract(year from activitydate),extract(MONTH from activitydate) order by extract(year from activitydate),extract(MONTH from activitydate)) rn1
            from updstats Where ACTIVITYDATE BETWEEN TO_DATE (:STARTDATE,'MM/DD/YYYY') AND TO_DATE(:ENDDATE,'MM/DD/YYYY')
            GROUP BY extract(year from activitydate), extract(MONTH from activitydate)
            order by yr, mon) as n 
       join (select extract(year from activitydate) as Pyr, 
           extract(MONTH from activitydate) as Pmon,             
           Sum(dicalls),
           row_number() over(partition by extract(year from activitydate) ,extract(MONTH from activitydate) order by extract(year from activitydate) ,extract(MONTH from activitydate) as rn2
            from updstats  Where ACTIVITYDATE BETWEEN add_months(TO_DATE (:STARTDATE,'MM/DD/YYYY'),-12) 
            AND add_months(TO_DATE(:ENDDATE,'MM/DD/YYYY'),-12)
            GROUP BY extract(year from activitydate), extract(MONTH from activitydate)
            order by Pyr, Pmon)) as p on (n.rn1=p.rn2) order by n.yr,n.mon

Answer 3

我会在月份和年份加入两个表格的结果

data.table

月份将是相同的，因此您只需要使每年与前一年匹配

Answer 4

只是因为没有人通过CTE回答，你走了

with tbl_A as (
select extract(year from activitydate) as yr, extract(MONTH from 
activitydate) as mon, Sum(dicalls)
from updstats
Where ACTIVITYDATE BETWEEN TO_DATE (:STARTDATE,'MM/DD/YYYY') AND 
TO_DATE(:ENDDATE,'MM/DD/YYYY')
GROUP BY extract(year from activitydate), extract(MONTH from activitydate)
order by yr, mon
),
tbl_B as(

select extract(year from activitydate) as Pyr, extract(MONTH from 
activitydate) as Pmon, Sum(dicalls)
from updstats
Where ACTIVITYDATE BETWEEN add_months(TO_DATE (:STARTDATE,'MM/DD/YYYY'),-12) 
AND add_months(TO_DATE(:ENDDATE,'MM/DD/YYYY'),-12)
GROUP BY extract(year from activitydate), extract(MONTH from activitydate)
order by Pyr, Pmon
)
select * from tbl_A a inner join tbl_B b on a.yr = b.yr and a.mon = b.mon;

如何从1个表中组合这两个Oracle查询

4 个答案: