如何在Java

时间:2018-10-08 02:04:59

标签: java recursion knapsack-problem

因此,如果您不了解背包问题是什么,这是一种从背包中提取不同重量的方法,以使它们加起来等于指定的总重量。这是我书中的示例,说明如果指定的总重量为20,如何解决问题。

Link to the image in my book

如果有人知道如何使用PLEASE递归帮助在Java中实现此问题,我会感到困惑。这是我的开始,但是我很确定这是错误的,我不知道现在要去哪里。

import java.util.*;

public class n01044854 {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.println("Please first enter a weight capacity up to a value of 
100, followed by a series of individual weight values with 25 weights being the max.)
");
        String values = input.nextLine();
        String[] tokens = values.split(" +");

        int capacity = Integer.parseInt(tokens[0]);
        int[] weightValues = new int[tokens.length - 1];
        for (int i = 0; i < tokens.length - 1; i++)
            weightValues[i] = Integer.parseInt(tokens[i+1]);
        optimizeWeights(capacity, weightValues, 0);
    }

    public static void optimizeWeights(int target, int[] weights, int currentIndex) {
        if (weights[currentIndex] == target)
            System.out.println("Success! Knapsack optimally filled.");
        else if (weights[currentIndex] < target) {
            int newTarget = target - weights[currentIndex];
            optimizeWeights(newTarget, weights, currentIndex + 1);
        } else if (weights[currentIndex] > target) {
            if (currentIndex < weights.length - 1)
                optimizeWeights(target, weights, currentIndex + 1);
            else
            //confused on what to do 
        }
    }
}

1 个答案:

答案 0 :(得分:0)

Look at the example

前一段时间,我在准备技术面试时就已经实施了它。