Question

我正在尝试制作一个三角函数计算器。

这是我的表单https://gyazo.com/6faecac18159d84b33497e06d864aa3d

当我输入3个数字时，应该得到正确的结果。实际结果的图片= https://gyazo.com/aa65ab502c0337ece0753b72029fa34a

但是我似乎无法弄清楚我的代码出了什么问题。

这是我的代码

            double B = Convert.ToDouble(textBox5.Text);
            double C = Convert.ToDouble(textBox1.Text);
            double side_A = 180 - B - C;
            string ConverterForA = Convert.ToString(side_A);
            textBox2.Text = ConverterForA;

            double calculatorForb = Math.Cos(C * (Math.PI / 180));
            string Converterforb = Convert.ToString(calculatorForb);
            textBox3.Text = Converterforb;

            double calculatorForc = Math.Sin(C * (Math.PI / 180));
            string ConverterForc = Convert.ToString(calculatorForc);
            textBox6.Text = ConverterForc;

三角形的边

        //double C = Convert.ToDouble(textBox1.Text);
        //double A = Convert.ToDouble(textBox2.Text);
        //double b = Convert.ToDouble(textBox3.Text);
        //double a = Convert.ToDouble(textBox4.Text);
        //double B = Convert.ToDouble(textBox5.Text);
        //double c = Convert.ToDouble(textBox6.Text);

您会看到结果混合在一起。我输入了10,50和80

Answer 1

我很难跟踪您的变量名以及要与之匹配的变量名，因此已经重命名了-我建议您仔细研究一下并使它们对您有意义。但是，以下工作（假设在输入数据时要小心-您显然需要在某些阶段添加一些验证。

double anglec = Convert.ToDouble(text_anglec.Text);
double angleb = Convert.ToDouble(text_angleb.Text);
//double anglea = Convert.ToDouble(text_anglea.Text);
double length1 = Convert.ToDouble(text_length1.Text);
//double length2 = Convert.ToDouble(text_length2.Text);
//double length3 = Convert.ToDouble(text_length3.Text);


double anglea = 180 - angleb - anglec;       
text_anglea.Text = anglea.ToString();

double length2 = length1 * Math.Sin(anglea * (Math.PI / 180));
text_length2.Text = length2.ToString();

double length3 = length1 *  Math.Cos(anglea * (Math.PI / 180));
text_length3.Text = length3.ToString();

C＃中的三角计算器

1 个答案: