Question

我正在学校的河内塔上工作，最终将需要7张光盘，但我无法弄清楚如何使用cout语句显示光盘的动作。例如，“将磁盘7从钉1移到钉3”。任何帮助，将不胜感激。 cout语句将位于moveDisk（）和Hanoi（）函数中。

#include <iostream>
#include <vector>
#include <string>
#include <cassert>

using namespace std;

struct pegType
{
    vector<int> diskStack;
    string pegName;
};

/***********************Function Prototypes************************/
void loadDisk(int totalDisks, vector<int>& startPeg);
void printPeg(vector<int> stack, string name);
void moveDisk(vector<int>& startPeg, vector<int>& goalPeg);
int hanoi(int totalDisks, vector<int>& startPeg, vector<int>& goalPeg, vector<int>& tempPeg);


int main()
{
    //Local Variables
    pegType peg1, peg2, peg3;
    peg1.pegName = "Peg1";
    peg2.pegName = "Peg2";
    peg3.pegName = "Peg3";

    const int NUM_DISKS(3);
    int totalMoves = 0;


    //Welcome Message
    cout << "Welcome to the Tower of Hanoi Simulator. This simulation will run with " << NUM_DISKS << " discs." << endl << endl;
    loadDisk(NUM_DISKS, peg1.diskStack);

    //Check the conditions of the pegs in the beginning
    cout << "The Starting Conditions of the three pegs: ";
    cout << endl; printPeg(peg1.diskStack, peg1.pegName);
    printPeg(peg2.diskStack, peg2.pegName);
    printPeg(peg3.diskStack, peg3.pegName);

    cout << endl << "Moves required to move " << NUM_DISKS << " discs from " << peg1.pegName << " to " << peg3.pegName << ": " << endl;
    totalMoves = hanoi(NUM_DISKS, peg1.diskStack, peg3.diskStack, peg2.diskStack);


    //Ending Conditions of the pegs and disks
    cout << endl << "The Ending Conditions of the three pegs: " << endl;
    printPeg(peg1.diskStack, peg1.pegName);
    printPeg(peg2.diskStack, peg2.pegName);
    printPeg(peg3.diskStack, peg3.pegName);

    cout << endl << "A stack of " << NUM_DISKS << " can be transfered in " << totalMoves << " moves.";
    cout << endl;
    system("pause");
    return 0;
}

/***********************Function Definitions*****************************/

//Load the discs into the vector
void loadDisk(int totalDisks, vector<int>& startPeg)
{
    for (int i = totalDisks; i > 0; i--)
    {
        startPeg.push_back(i);
    }
}

//Print the disk Numbers backwards (3, 2, 1) to the user
void printPeg(vector<int> stack, string name)
{
    if (stack.size() > 1)
    {
        cout << name << " has " << stack.size() << " discs: ";
        assert(stack.size() > 0);
        for (unsigned int i = 0; i < stack.size(); i++)
        {
            cout << stack[i] << " ";
        }
    }
    else
    {
        cout << name << " has " << stack.size() << " discs: ";
    }

    cout << endl;
}

//Moves the bottom disk to the goal
void moveDisk(vector<int>& startPeg, vector<int>& goalPeg)
{
    if (startPeg.size() > 0)
    {
        int temp = startPeg.back();
        startPeg.pop_back();
        goalPeg.push_back(temp);
    }
}

//A recursive function that handles the disk transfer
//Displays the moves made
int hanoi(int totalDisks, vector<int>& startPeg, vector<int>& goalPeg, vector<int>& tempPeg)
{
    int count = 0;

    if (totalDisks > 0)
    {
        count = hanoi(totalDisks - 1, startPeg, goalPeg, tempPeg);
        moveDisk(startPeg, goalPeg);
        count++;
        count += hanoi(totalDisks - 1, tempPeg, goalPeg, startPeg);
    }
    return count;
}

Answer 1

在函数struct Peg和std::vector中使用Hanoii()作为参数（而不是MoveDisk()），以便函数可以正确知道要打印的源名称和目标名称。

struct pegType
{
    vector<int> diskStack;
    string pegName;
};

/***********************Function Prototypes************************/
void loadDisk(int totalDisks, vector<int>& startPeg);
void printPeg(vector<int> stack, string name);
void moveDisk(pegType& source, pegType& dest);
int hanoi(int totalDisks, pegType& source, pegType& dest, pegType& aux);


int main()
{
    //Local Variables
    pegType peg1, peg2, peg3;
    peg1.pegName = "Peg1";
    peg2.pegName = "Peg2";
    peg3.pegName = "Peg3";

    const int NUM_DISKS(3);
    int totalMoves = 0;


    //Welcome Message
    cout << "Welcome to the Tower of Hanoi Simulator. This simulation will run with " << NUM_DISKS << " discs." << endl << endl;
    loadDisk(NUM_DISKS, peg1.diskStack);

    //Check the conditions of the pegs in the beginning
    cout << "The Starting Conditions of the three pegs: ";
    cout << endl; printPeg(peg1.diskStack, peg1.pegName);
    printPeg(peg2.diskStack, peg2.pegName);
    printPeg(peg3.diskStack, peg3.pegName);

    cout << endl << "Moves required to move " << NUM_DISKS << " discs from " << peg1.pegName << " to " << peg3.pegName << ": " << endl;
    totalMoves = hanoi(NUM_DISKS, peg1, peg3, peg2);


    //Ending Conditions of the pegs and disks
    cout << endl << "The Ending Conditions of the three pegs: " << endl;
    printPeg(peg1.diskStack, peg1.pegName);
    printPeg(peg2.diskStack, peg2.pegName);
    printPeg(peg3.diskStack, peg3.pegName);

    cout << endl << "A stack of " << NUM_DISKS << " can be transfered in " << totalMoves << " moves.";
    cout << endl;
    system("pause");
    return 0;
}

/***********************Function Definitions*****************************/

//Load the discs into the vector
void loadDisk(int totalDisks, vector<int>& startPeg)
{
    for (int i = totalDisks; i > 0; i--)
    {
        startPeg.push_back(i);
    }
}

//Print the disk Numbers backwards (3, 2, 1) to the user
void printPeg(vector<int> stack, string name)
{
    if (stack.size() > 1)
    {
        cout << name << " has " << stack.size() << " discs: ";
        assert(stack.size() > 0);
        for (unsigned int i = 0; i < stack.size(); i++)
        {
            cout << stack[i] << " ";
        }
    }
    else
    {
        cout << name << " has " << stack.size() << " discs: ";
    }

    cout << endl;
}

//Moves the bottom disk to the goal
void moveDisk(pegType& source, pegType& dest)
{
    if (source.diskStack.size() > 0)
    {       
        int temp = source.diskStack.back();
        source.diskStack.pop_back();
        dest.diskStack.push_back(temp);
        std::cout << "Moving disk# " << temp << " from " << source.pegName << " to " << dest.pegName << '\n';
    }
}

//A recursive function that handles the disk transfer
//Displays the moves made
int hanoi(int totalDisks, pegType& source, pegType& dest, pegType& aux)
{
    int count = 0;

    if (totalDisks > 0)
    {
        count = hanoi(totalDisks - 1, source, aux, dest);
        moveDisk(source, dest);
        count++;
        count += hanoi(totalDisks - 1, aux, dest, source);
    }
    return count;
}

输出：

河内塔与递归和向量

1 个答案: