未来价值计算

Question

我正在尝试制作一个简单的复合和年度投资计算器，但是有一个我无法发现的错误。我是否错过了for或while循环？

var sourceService = new Stripe.StripeSourceService();

// Get customer with current payment source.
var stripeCustomer = customerService.Get(stripeCustomerWithAccount.Id, new Stripe.StripeRequestOptions { ApiKey = ConfigurationManager.AppSettings["StripeSecretKey"] });

// Set Stripe Customer Id and Stripe Token options.
var tokenService = new Stripe.StripeTokenService();
var stripeToken = tokenService.Get(tokenId, new Stripe.StripeRequestOptions { ApiKey = ConfigurationManager.AppSettings["StripeSecretKey"] });

// Check if credit card already exists.
if (!CreditCardExists(stripeCustomer, stripeToken))
{
    // Create new credit card.
    var sourceOptions = new StripeNet.StripeSourceCreateOptions()
    {
        Customer = stripeCustomer.Id,
        Card = new StripeNet.StripeCreditCardOptions
        {
            TokenId = stripeToken.StripeCard.Id 
        }                            
    };

    var source = sourceService.Create(sourceOptions, new Stripe.StripeRequestOptions { ApiKey = ConfigurationManager.AppSettings["StripeSecretKey"] });
}

Answer 1

未来价值计算

print("Investment Calculator")
print(f"=====================")
present_value = int(input("Principal Amount? "))
interest_rate = float(input("Annual Interest Rate? "))
terms_in_years = int(input("Number of Years? "))

future_value = present_value * pow((1 + (interest_rate / 100)), terms_in_years)
result = float("{:.2f}".format(future_value))

print(f"Future Value is: {result}")"

Answer 2

数字对我来说看起来很好。（1000 + .01 + 10）：

def formatInterest(t):
    return "{:>3} {:<10}".format(t[0],round(t[1],2))

investment=float(input("Enter an initial investment."))
interest=float(input("Enter an interest rate between .01 to .10."))
years=int(input("Enter a number of years between 1 to 30."))

print(*list(map(formatInterest,enumerate([investment * (interest+1) ** i
                                          for i in range(years+1)]))),sep="\n")

输出：

您可以在此处了解有关map（），enumerate（）和print（）的信息：

列表推导产生每年的值，从0到10（输入）开始。 enumerate添加formatInterest-input-tuple的年份。 map应用格式，print()使用所有已分解列表上的换行符sep将其全部打印出来。

python3中的简单且复合的年度投资计算器

2 个答案:

未来价值计算