Question

我有一个程序（futval.py），可以计算10年后的投资价值。我想修改该计划，以便计算10年后的年度投资价值，而不是计算10年后一次性投资的价值。我想这样做而不使用累加器变量。是否可以仅使用原始程序中存在的变量（投资，apr，i）来执行此操作？

# futval.py
# A program to compute the value of an investment
# carried 10 years into the future

def main():
    print "This program calculates the future value",
    print "of a 10-year investment."

    investment = input("Enter the initial investment: ")
    apr = input("Enter the annual interest rate: ")

    for i in range(10):
        investment = investment * (1 + apr)

    print "The value in 10 years is:", investment

main()

如果不引入“未来”，我无法完成修改程序。累加器变量。

# futval10.py
# A program to compute the value of an annual investment
# carried 10 years into the future

def main():
    print "This program calculates the future value",
    print "of a 10-year annual investment."

    investment = input("Enter the annual investment: ")
    apr = input("Enter the annual interest rate: ")

    futval = 0

    for i in range(10):
        futval = (futval + investment) * (1+apr)

    print "The value in 10 years is:", futval

main()

Answer 1

好的，如果你尝试做一些数学运算，你会自己看到解决方案。我们有第一年：

new_value = investment*(1 + apr)

第二个：

new_second_value = (new_value + investment)*(1+apr)

或

new_second_value = (investment*(1 + apr) + investment)*(1+apr)

等等。如果你真的尝试乘以这些东西，你会看到10年后的最终值是

investment*((1+apr)**10) + investment*((1+apr)**9)+...   etc

所以问题的解决方案只是

print("The value in 10 years is:", sum([investment*((1+apr)**i) for i in range(1, 11)]))

编辑：不知怎的，我设法忽略了这样一个事实：我写的只是一个几何系列，所以答案更简单：

ten_years_annual_investment = investment*(apr+1)*((apr+1)**10 - 1)/apr

Answer 2

嗯，您不需要累加器，但您仍需要一个临时变量来保存定期投资的原始值：

def main():
    print "This program calculates the future value",
    print "of a 10-year investment."

    investment = input("Enter the initial investment: ")
    apr = input("Enter the annual interest rate: ")

    hold = investment
    investment = investment / apr

    for i in range(10):
        investment = investment * (1 + apr)

    investment = investment - hold / apr

    print "The value in 10 years is:", investment

main()

Python - 年度投资的累计价值

2 个答案: