我不得不做一个剪刀石头布游戏，在那儿你要在电脑上玩。 1,2,3用于石头，纸张，剪刀。它循环5次，并显示计算机获胜和玩家获胜的数量。除了循环之外，我已完成所有工作。当您输入大于3的数字时，假设您说“无效”并循环播放，直到您玩5个有效游戏为止。但是，如果您输入错误的答案数量奇异，它会使您玩6场游戏，而如果您输入错误的答案数量偶数，它将使您玩5场游戏。我需要它使您能够玩5场比赛，无论奇数或偶数错了。请帮忙。
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
int player = 0, computer = 0;
int computerScore = 0, playerScore = 0;
int loops = 0;
int rock = 1;
int paper = 2;
int scissors = 3;
for (int i = 1; i < 6; i++) {
computer = (int) (Math.random() * 3) + 1;
System.out.println("Enter 1 for Rock, 2 for Paper, 3 for Scissors");
player = reader.nextInt();
if (player > scissors) {
System.out.println("Not a valid response");
System.out.println("Enter 1 for Rock, 2 for Paper, 3 for Scissors");
player = reader.nextInt();
i--;
}
if (player == computer) {
System.out.println("Tie");
} else if (player == rock) {
if (computer == paper) {
System.out.println("Player picked Rock, Computer picked Paper, Computer wins");
computerScore++;
} else if (computer == scissors) {
System.out.println("Player picked Rock, Computer picked Scissors, Player wins");
playerScore++;
}
} else if (player == paper) {
if (computer == rock) {
System.out.println("Player picked Paper, Computer picked Rock , Player wins");
playerScore++;
} else if (computer == scissors) {
System.out.println("Player picked Paper, Computer picked Scissors, Computer wins");
computerScore++;
}
} else if (player == scissors) {
if (computer == rock) {
System.out.println("Player picked Scissors, Computer picked Rock , Computer wins");
computerScore++;
} else if (computer == paper) {
System.out.println("Player picked Scissors, Computer picked Paper, Player wins");
playerScore++;
}
}
}
System.out.println("");
System.out.println("Computer Wins " + computerScore);
System.out.println("Player Wins " + playerScore);
}
答案 0 :(得分：1)
为了使事情变得容易，我建议使用while循环。
E.G：
func processString(_ s: String) ->Bool {
var sum = 0
for char in s{
if let number = Int(String(char)) {
// number is not nil
}
}
}
答案 1 :(得分：0)
您的代码逻辑不正确。我已经使用枚举Options对其进行了重组，以保存岩石，纸张和剪刀的值。我还使用了Player类，可以用作用户或计算机，或者将来用作其他播放器。
枚举可容纳岩石，纸张和剪刀的所有可能值
enum Options {
ROCK(1), PAPER(2), SCISSORS(3);
private Options(int item) {
this.item = item;
}
private final int item;
public int getItem() {
return item;
}
}
将Class Player设置为“用户”或“计算机”
class Player {
private int score;
private int input;
public int getScore() {
return score;
}
public void setScore(int score) {
this.score = score;
}
public int getInput() {
return input;
}
public void setInput(int input) {
this.input = input;
}
}
最后，主类带有其他一些实用方法
public class Game {
private static int MAX_ATTEMPTS = 5;
// main method
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
Player user = new Player();
Player comp = new Player();
int input = 0;
while (MAX_ATTEMPTS > 0) {
// reading input till it's right!
while (true) {
try {
System.out.println("Enter 1 for Rock, 2 for Paper, 3 for Scissors");
input = reader.nextInt();
// valid only if its one of the above
if (input == Options.PAPER.getItem() || input == Options.SCISSORS.getItem() || input == Options.ROCK.getItem()) {
user.setInput(input);
comp.setInput(fetchComputerInput());
computeHigherHand(user, comp);
MAX_ATTEMPTS--;
break;
} else {
System.err.println("Invalid input");
reader.next();
}
} catch (Exception e) {
System.err.println("Invalid input");
reader.next();
}
}
}
checkWinner(user, comp);
reader.close();
}
}
返回计算机分数的方法
public static int fetchComputerInput() {
return (int) (Math.random() * 3) + 1;
}
确定较高手牌的方法
public static void computeHigherHand(Player user, Player comp) {
// when user enters 'rock'
if (user.getInput() == Options.ROCK.getItem()) {
// comp wins
if (comp.getInput() == Options.PAPER.getItem()) {
System.out.println("Player picked Rock, Computer picked Paper, Computer wins");
comp.setScore(comp.getScore() + 1);
}
// user wins
else if (comp.getInput() == Options.SCISSORS.getItem()) {
System.out.println("Player picked Rock, Computer picked Scissors, Player wins");
user.setScore(user.getScore() + 1);
}
// draw
else {
System.out.println("Player picked Rock, Computer picked Rock, Draw");
}
}
// when user enters 'paper'
if (user.getInput() == Options.PAPER.getItem()) {
// user wins
if (comp.getInput() == Options.ROCK.getItem()) {
System.out.println("Player picked Paper, Computer picked Rock , Player wins");
user.setScore(user.getScore() + 1);
}
// comp wins
else if (comp.getInput() == Options.SCISSORS.getItem()) {
System.out.println("Player picked Paper, Computer picked Scissors, Computer wins");
comp.setScore(comp.getScore() + 1);
}
// draw
else {
System.out.println("Player picked Paper, Computer picked Paper, Draw");
}
}
// when user enters 'scissors'
if (user.getInput() == Options.SCISSORS.getItem()) {
// comp wins
if (comp.getInput() == Options.ROCK.getItem()) {
System.out.println("Player picked Scissors, Computer picked Rock , Computer wins");
comp.setScore(comp.getScore() + 1);
}
// user wins
else if (comp.getInput() == Options.PAPER.getItem()) {
user.setScore(user.getScore() + 1);
System.out.println("Player picked Scissors, Computer picked Paper, Player wins");
}
// draw
else {
System.out.println("Player picked Scissors, Computer picked Scissors, Draw");
}
}
}
确定获胜者的方法
public static void checkWinner(Player user, Player comp) {
// check who won
if (user.getScore() > comp.getScore())
System.out.println("User wins! User score : " + user.getScore() + " Comp score : " + comp.getScore());
else if (user.getScore() < comp.getScore())
System.out.println("Comp wins! User score : " + user.getScore() + " Comp score : " + comp.getScore());
else
System.out.println("Tie");
}
让我知道是否需要进一步说明。