摇滚纸剪刀游戏

时间:2015-10-17 19:48:44

标签: python loops if-statement

我目前非常喜欢这种摇滚,纸张,剪刀程序,非常感谢一些帮助。我查看过有关摇滚,纸张,剪刀节目的其他帖子,但我仍然坚持。

我目前收到的错误是当我要求用户选择“摇滚”,“纸张”时。或者'剪刀'它会继续问几次然后我得到一个错误。另外,在我看来,我看到的很多帖子都涉及到我在课堂上没有使用的概念,所以我对它们感到不舒服。

      choices = [ 'Rock', 'Paper', 'Scissors' ]
# 1. Greetings & Rules
def showRules():
    print("\n*** Rock-Paper-Scissors ***\n")

    print("\nEach player chooses either Rock, Paper, or Scissors."
          "\nThe winner is determined by the following rules:"
          "\n   Scissors cuts Paper   ->  Scissors wins"
          "\n   Paper covers Rock     ->  Paper wins"
          "\n   Rock smashes Scissors ->  Rock wins\n")

# 2. Determine User Choice
def getUserChoice():
    usrchoice = input("\nChoose from Rock, Paper or Scissors: ").lower()
    if (usrchoice not in choices):
        usrchoice = input("\nChoose again from Rock, Paper or Scissors: ").lower()
    print('User chose:', usrchoice)
    return usrchoice

# 3. Determine Computer choice
def getComputerChoice():
    from random import randint
    randnum = randint(1, 3)
    cptrchoice = choices(randnum)
    print('Computer chose:', cptrchoice)
    return randnum

# 4. Determine Winner
def declareWinner(user, computer):
    if usrchoice == cptrchoice:
        print('TIE!!')
    elif (usrchoice == 'Scissors' and cptrchoice == 'Rock'
         or usrchoice == 'Rock' and cptrchoice == 'Paper'
         or usrchoice == 'Paper' and cptrchoice == 'Scissors'):
        print('You lose!! :(')
    else:
        print('You Win!! :)')


#5. Run program
def playGame():
    showRules()                     # Display the title and game rules
    user = getUserChoice()       # Get user selection (Rock, Paper, or Scissors)
    computer = getComputerChoice()  # Make and display computer's selection
    declareWinner(user, computer)   # decide and display winner

1 个答案:

答案 0 :(得分:1)

您的代码几乎没有问题:

首先,您要将user input转换为小写,但您的列表项不是。因此检查将失败。

choices = [ 'rock', 'paper', 'scissors' ]

第二件事是你调用选择(randnum)会抛出错误,因为你必须使用[]从列表中检索元素。

cptrchoice = choices[randnum]

如果您输入无效字符串,则会发生第三种情况。您只需查看if,但需要while loop

while (usrchoice not in choices):
    usrchoice = getUserChoice() #input("\nChoose again from Rock, Paper or Scissors: ").lower()

第四个是declareWinnerparamsusercomputer,但是你在{{1}使用usrchoicecptrchoice条件

if

试试这个并试一试