Question

我有2张桌子PLAYER和MATCHES

CREATE TABLE PLAYER 
(
id int PRIMARY KEY,
name varchar(255),
salary int
);
INSERT INTO PLAYER values(1,'MOHIT',1000);
INSERT INTO PLAYER values(2,'MNOP',2000);
INSERT INTO PLAYER values(3,'ABC',100);
INSERT INTO PLAYER values(4,'XYZ',10);

CREATE TABLE MATCHES 
(
id int,
player_id int,
scores int
);
INSERT INTO MATCHES values(1,1,100);
INSERT INTO MATCHES values(2,2,52);
INSERT INTO MATCHES values(3,3,10);
INSERT INTO MATCHES values(4,1,200);
INSERT INTO MATCHES values(5,1,300);

谁能告诉我MYSQL查询来找到MOHIT打进双世纪比赛（200次）的比赛次数。

我使用了以下查询，但给了我SQL错误。

查询：-

 SELECT FIND_IN_SET(Select m.id from MATCHES m
  JOIN PLAYER p
  on p.id=m.player_id
  WHERE p.name='MOHIT'
  AND m.scores>=200 
  ORDER BY m.scores limit 1,(SELECT GROUP_CONCAT(
  SELECT m.id from MATCHES m 
  JOIN PLAYER p
  on p.id=m.player_id
  WHERE p.name='MOHIT'
  ))) AS RANK;

在此查询中，我试图找到MOHIT为其赢得双世纪的第一个match_id，然后在他参加的所有比赛中找到该match_id的排名。

由于MOHIT玩了2场游戏得分200或超过200，则预期输出应为2。

我们将不胜感激任何帮助。

Answer 1

如果我的理解正确，则可以使用MYSQL COUNT（）达到要求

SELECT COUNT(*) AS no_of_match 
FROM   matches m 
       JOIN player p 
         ON p.id = m.player_id 
WHERE  p.NAME = 'MOHIT' 
       AND m.scores >= 200;

Answer 2

用例何时

SELECT p.name ,sum(case when scores>=200 then 1 else 0 end) AS no_of_match_200 
    FROM   matches m 
           JOIN player p 
             ON p.id = m.player_id 

   where p.name ='MOHIT'
   group by p.name

http://sqlfiddle.com/#!9/1762cb/7

name    no_of_match_200
MOHIT   2

Answer 3

在此解决方案中，内部查询会计算出累积得分和所打比赛的计数，外部查询会找到累积得分符合您的边界条件的最早比赛。

select p.name,min(s.matchesplayed) matchesplayed
from player p
join
(

select m.player_id,
        (select sum(m1.scores) from matches m1 where m1.player_id = m.player_id and m1.id <= m.id) sumscore,
        (select count(m1.scores) from matches m1 where m1.player_id = m.player_id and m1.id <= m.id) matchesplayed
from matches m

) s on s.player_id = p.id
where  # p.name =  'mohit' and 
        sumscore>= 200
group by p.name;

在这种情况下，我的查询将找到任何玩家。

Answer 4

我会这样：

select count(*)
from players p join
     matches m
     on p.id = m.player_id
where p.name = 'Mohit' and
      m.id < (select min(m2.id)
              from matches m2 
              where m2.player_id = m.player_id and
                    m2.score >= 200
             );

MYSQL查询以找到RANK

4 个答案: