找到用户测试MySQL的排名

Question

这是目前获取所有用户排名的MySQL查询。但我想获取特定的用户排名。

SELECT Percentage_of_Marks,mark,test_id,
       1+(SELECT count(*) from user_test a
          WHERE a.Percentage_of_Marks > b.Percentage_of_Marks) as RNK,
       Percentage_of_Marks
FROM user_test b
ORDER BY b.Percentage_of_Marks DESC

我的查询结果是。

如何查找特定test_id的RNK。

Answer 1

-g