Question

我有一个包含Child_ID，Test_ID和Test_Date

的表

 Child_ID Test_ID     Test_Date
   1        1        2018-05-21
   1        2        2018-05-22

我想找到TestNumber，所以我正在使用Rank on fly

Select Child_ID, Test_ID ,Test_Date,RANK() OVER (PARTITION BY t.Child_id order by Test_Date asc,boe.Test_ID asc) AS [TEST_NUMB]
from [Test] T
where t.Child_ID in (1)

给我结果

Child_ID Test_ID     Test_Date    TEST_NUMB
1           1        2018-05-21       1
1           2        2018-05-22       2

但问题是当我只选择一个测试ID时，Test_number每次都会给出'1'

select * from Test where test_ID =1 

    Child_ID Test_ID     Test_Date    TEST_NUMB
    2560249     1        2018-05-21       1

select * from Test where test_ID =2 

    Child_ID Test_ID     Test_Date    TEST_NUMB
    2560249     1        2018-05-21       1

我是否可以根据Test_Date获取查询以获取确切的test_number，而不插入临时表（我有数百万条记录）

Answer 1

将当前查询放入CTE，然后查询：

WITH cte AS (
    SELECT Child_ID, Test_ID ,Test_Date,
        RANK() OVER (PARTITION BY Child_id ORDER BY Test_Date, Test_ID) AS [TEST_NUMB]
    FROM [Test]
    WHERE Child_ID IN (1)
)

SELECT * FROM cte WHERE test_ID = 1;

这应该有效，因为当你用精确的test_ID查询时，等级值已经实现了（对不起，我只是想使用那个词）。

Answer 2

同样是蒂姆的CTE

select * 
from ( Select Child_ID, Test_ID , Test_Date
            , RANK() OVER (PARTITION BY t.Child_id 
                           order by Test_Date asc, Test_ID asc) AS [TEST_NUMB]
        from [Test] T
       where Child_ID = 1 
     ) tt 
where Test_ID = 1

SQL Query查找Rank

2 个答案: