Question

我正在通过Python库marketo-rest-python使用Marketo API。我可以创建销售线索，也可以通过以下基本代码对其进行更新：

leads = [{"email":"joe@example.com","firstName":"Joe"},{"email":"jill@example.com","firstName":"Jill"}]
lead = mc.execute(method='create_update_leads', leads=leads, action='createOnly', lookupField='email', 
                asyncProcessing='false', partitionName='Default')

当我以编程方式创建时，此“领导” JSON对象通过

leads = []

lead = {}
lead['email'] = "joe@example.com"
lead['firstName'] = "Joe"
leads.append(lead)

lead = {}
lead['email'] = "jill@example.com"
lead['firstName'] = "Jill"
leads.append(lead)

json_leads = json.dumps(leads, separators=(',', ':'))

print(json_leads)

然后，Microsoft Azure Databricks中的输出完全相同，但是Marketo系统返回一个609->无效的JSON。

我的输出看起来像

[{"email":"joe@example.com","firstName":"Joe"},{"email":"jill@example.com","firstName":"Jill"}]

与示例中的完全相同。当我使用示例JSON代码行时，它可以工作，但是我自己生成的JSOn不起作用。

任何人都知道这会是什么？我在Microsoft Azure Databricks中使用Python。

Answer 1

我相信您无需致电json.dumps，只需这样做

leads = []

lead = {}
lead['email'] = "joe@example.com"
lead['firstName'] = "Joe"
leads.append(lead)

lead = {}
lead['email'] = "jill@example.com"
lead['firstName'] = "Jill"
leads.append(lead)

lead = mc.execute(method='create_update_leads', leads=leads, action='createOnly', 
lookupField='email', asyncProcessing='false', partitionName='Default')

手动生成的JSON可以工作，但是通过json.dumps创建的JSON即使输出看起来完全相同也不起作用

1 个答案: