Question

我创建了一些混乱的字符串，并试图对其进行修复。最终，我遇到了这样的问题：我的函数不起作用，但是手动键入的相同代码起作用。

问题： 为什么在Python中，相同的代码不能在函数中起作用，但是当您手动编码完全相同的代码时却可以起作用？

代码如下：

    #A variable
    x = "apples and oranges!"

    #Making a variable messed up strings
    x = "-".join(x)
    x = str(x.split("-"))


    #Creating automatic function for cleaning messed up strings
    def clnStr(x):
        y = x
        y = y.replace("'", "")
        y = y.replace(",", "")
        y = y.replace("[", "")
        y = y.replace("]", "")
        y = y.replace(",", "")
        y = y.replace(" ", "")
    clnStr(x)
    print(x)



    #Cleaning up string variable manually
    y = x
    y = y.replace("'", "")
    y = y.replace(",", "")
    y = y.replace("[", "")
    y = y.replace("]", "")
    y = y.replace(",", "")
    y = y.replace(" ", "")
    print(y)

# Repairing string variable
for i, index in enumerate(y): #Getting a list of indexes of a string variable
    print(i, index)

y = y[0:6] + " " + y[6:9] + " " + y[9:]
print(y)


#cannot repair 'x' variable with same method because the function does not work as it should.

Answer 1

您没有从clnStr函数返回任何内容。试试：

def clnStr(x):
    y = x
    y = y.replace("'", "")
    y = y.replace(",", "")
    y = y.replace("[", "")
    y = y.replace("]", "")
    y = y.replace(",", "")
    y = y.replace(" ", "")
    return y

z = clnStr(x)
print(z)

＃为什么在Python清理字符串中手动起作用，但是创建完全相同的函数却不起作用？

1 个答案: