我有以下代码:
import json
src_vol1 = {'provider_id':'src1'}
src_vol2 = {'provider_id':'src2'}
get_snapshot_params = lambda src_volume, trg_volume: {
'volumeId': src_volume['provider_id'],
'snapshotName': trg_volume['id']}
trg_vol1 = {'id':'trg1'}
trg_vol2 = {'id':'trg2'}
src_vols = [src_vol1, src_vol2]
trg_vols = [trg_vol1, trg_vol2]
snapshotDefs = map(get_snapshot_params , src_vols, trg_vols)
params = {'snapshotDefs': snapshotDefs}
json.dumps(params)
我需要它在Python3和Python2.7上工作,但在Python3上我得到
Traceback (most recent call last):
File "./prog.py", line 16, in <module>
File "/usr/lib/python3.4/json/__init__.py", line 230, in dumps
return _default_encoder.encode(obj)
File "/usr/lib/python3.4/json/encoder.py", line 192, in encode
chunks = self.iterencode(o, _one_shot=True)
File "/usr/lib/python3.4/json/encoder.py", line 250, in iterencode
return _iterencode(o, 0)
File "/usr/lib/python3.4/json/encoder.py", line 173, in default
raise TypeError(repr(o) + " is not JSON serializable")
TypeError: <map object at 0xb72a1a0c> is not JSON serializable
我试图把dict()放在params周围,但它没有用。 有什么不同?我在文档中找不到任何内容。
答案 0 :(得分:4)
要重现python2行为,请将list(map(...))
替换为map
。
这仍然可以在python2中运行,但是在python2中,它会使try:
from itertools import imap as map # py2
except ImportError:
pass # py3, map is already defined apropriately
返回的列表有一个无意义的额外副本,这会占用更多内存并运行得更慢。
为避免这种情况,您可以尝试以下方法:
{{1}}
答案 1 :(得分:0)
或者您也可以检查系统版本,然后根据系统版本将map
重新定义为map_
:
import sys
ver = sys.version[:3]
if ver < '3': #Python 2
map_ = map #use same map method
elif ver >= '3': #Python 3
map_ = lambda f,x : list(map(f,x))
snapshotDefs = map_(get_snapshot_params , src_vols, trg_vols)