Question

我已经使用库lubridate来查找开始时间和结束时间之间的时差。这是我的代码：

library(lubridate)

a <- read.csv("C:/Users/Desktop/Dump.csv")

b <- a$StartTime 
c <- a$EndTime

hm(c)- hm(b)

这是代码的结果：

   [1] "1H -18M 0S" "1H 5M 0S"   "1H 16M 0S"  "1H 16M 0S"  "1H 5M 0S"   "1H 16M 0S"  "1H 18M 0S" 
   [8] "44M 0S"     "1H 0M 0S"   "1H 23M 0S"  "2H -41M 0S" "1H -18M 0S" "1H -18M 0S" "1H -16M 0S"
  [15] "1H 0M 0S"   "41M 0S"     "1H 0M 0S"   "24M 0S"     "1H -20M 0S" "1H 0M 0S"   "1H -19M 0S"
  [22] "1H 16M 0S"  "1H 25M 0S"  "1H 10M 0S"  "1H 16M 0S"  "44M 0S"     "1H 18M 0S"  "1H 23M 0S" 
  [29] "1H -19M 0S" "1H 6M 0S"   "1H 16M 0S"  "1H -19M 0S" "1H -17M 0S" "1H -20M 0S" "1H 0M 0S"  
  [36] "2H -40M 0S" "2H -40M 0S" "1H -20M 0S" "1H -20M 0S" "1H 5M 0S"   "1H 17M 0S"  "1H 11M 0S" 
  [43] "1H -23M 0S" "1H -30M 0S" "1H -29M 0S" "1H -19M 0S" "45M 0S"     "1H -19M 0S" "1H 1M 0S"  
  [50] "1H -6M 0S"  "30M 0S"     "1H 28M 0S"  "1H -21M 0S" "30M 0S"     "1H 1M 0S"   "1H -10M 0S"
  [57] "1H 0M 0S"   "1H -28M 0S" "42M 0S"     "51M 0S"     "52M 0S"     "1H 17M 0S"  "2H -43M 0S"
  [64] "1H -19M 0S" "1H 1M 0S"   "1H -26M 0S" "50M 0S"     "1H -19M 0S" "1H 0M 0S"   "1H -23M 0S"
  [71] "1H 2M 0S"   "40M 0S"     "30M 0S"     "1H -15M 0S" "1H -6M 0S"  "30M 0S"     "1H -33M 0S"
  [78] "1H -20M 0S" "1H 4M 0S"   "41M 0S"     "1H 13M 0S"  "1H 0M 0S"   "1H 0M 0S"   "1H -30M 0S"
  [85] "29M 0S"     "1H 10M 0S"  "1H 5M 0S"   "1H 0M 0S"   "1H -27M 0S" "51M 0S"     "1H -5M 0S" 
  [92] "31M 0S"     "1H -30M 0S" "33M 0S"     "1H 0M 0S"   "36M 0S"     "2H -43M 0S" "1H -30M 0S"
  [99] "34M 0S"     "50M 0S"     "1H -31M 0S" "41M 0S"     "50M 0S"     "1H -15M 0S" "1H -15M 0S"

这是我的结果，但分钟数为负，这意味着正确的答案是“小时-分钟”。任何人都知道我的代码在哪里是错误的，或者我忘记编写任何代码。

数据的格式是因子。

Answer 1

您可能拥有信号时间数据库（给出的代码不会重现这种结果）。但是，请尝试计算经过的时间（time2-time3或time2％-％time3）和使用时间，以正确的格式

pip install --only-binary :all: mysqlclient

R找到持续时间

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