我有一组整数值,我想将它们设置为Weibull分布并获得最佳拟合参数。然后,使用最佳拟合参数绘制数据的直方图以及Weibull分布的pdf。这是我使用的代码。
from jtlHandler import *
import warnings
import numpy as np
import pandas as pd
import scipy.stats as st
import matplotlib
matplotlib.use('Agg')
import matplotlib.pyplot as plt
def get_pdf(latencies):
a = np.array(latencies)
ag = st.gaussian_kde(a)
ak = np.linspace(np.min(a), np.max(a), len(a))
agv = ag(ak)
plt.plot(ak,agv)
plt.show()
return (ak,agv)
def fit_to_distribution(distribution, data):
params = distribution.fit(data)
# Return MLEs for shape (if applicable), location, and scale parameters from data.
#
# MLE stands for Maximum Likelihood Estimate. Starting estimates for the fit are given by input arguments; for any arguments not provided with starting estimates, self._fitstart(data) is called to generate such.
return params
def make_distribution_pdf(dist, params, end):
arg = params[:-2]
loc = params[-2]
scale = params[-1]
# Build PDF and turn into pandas Series
x = np.linspace(0, end, end)
y = dist.pdf(x, loc=loc, scale=scale, *arg)
pdf = pd.Series(y, x)
return pdf
latencies = getLatencyList("filename")
latencies = latencies[int(9*(len(latencies)/10)):len(latencies)]
data = pd.Series(latencies)
params = fit_to_distribution(st.weibull_max, data)
print("Parameters for the fit: "+str(params))
# Make PDF
pdf = make_distribution_pdf(st.weibull_max, params, max(latencies))
# Display
plt.figure()
ax = pdf.plot(lw=2, label='PDF', legend=True)
data.plot(kind='hist', bins=200, normed=True, alpha=0.5, label='Data',
legend=True, ax=ax)
ax.set_title('Weibull distribution')
ax.set_xlabel('Latnecy')
ax.set_ylabel('Frequency')
plt.savefig("image.png")
可以看出,威布尔近似与原始数据分布不相似。
如何获得最佳的威布尔近似值?
答案 0 :(得分:0)
您可以使用以下两种方法使数据集(数字集)适合任何分布。
import os
import matplotlib.pyplot as plt
import sys
import math
import numpy as np
import scipy.stats as st
from scipy.stats._continuous_distns import _distn_names
from scipy.optimize import curve_fit
def fit_to_distribution(distribution, latency_values):
distribution = getattr(st, distribution)
params = distribution.fit(latency_values)
return params
def make_distribution_pdf(distribution, latency_list):
distribution = getattr(st, distribution)
params = distribution.fit(latency_list)
arg = params[:-2]
loc = params[-2]
scale = params[-1]
x = np.linspace(min(latency_list), max(latency_list), 10000)
y = distribution.pdf(x, loc=loc, scale=scale, *arg)
return x, y