Question

首先要注意几件事：

我正在使用Windows 10家庭版
我正在使用Python 3.7
我正在使用pygame 1.9.4
我的IDE是Visual Studio Code，以IDLE作为备份

我目前正在使用pygame设计GUI。注意：代码尚未完成。

当我使用VS Code运行调试会话时，它（通常）可以按预期运行，但是当我尝试单击“开始”按钮时，pygame无法响应，并且显示为无响应。

我在制作的其他pygame脚本中也注意到了这一点，在pygame窗口中，单击或移动它们会冻结。

任何帮助将不胜感激。

代码如下：

# Import modules
import sys, pygame, time, math
from time import sleep
from PIL import Image

# Display background image
image = 'asdf.png'
change = 2
img = Image.open('asdf.png')
width = img.width * change
height = img.height * change
print(width)
print(height)
screen = pygame.display.set_mode((width,height))
background = pygame.image.load(image).convert()
newscreen = pygame.transform.scale(background, (width, height))
screen.blit(newscreen, (0,0))
pygame.display.update()

# start button
pygame.draw.rect(newscreen, (255,120,0), pygame.Rect(width/4,height-height/4, width/2, height/7))
screen.blit(newscreen, (0,0))
pygame.display.update()
pygame.init()
myFont = pygame.font.SysFont("Times New Roman", 100)
text = myFont.render("START", False, (0, 0, 0))
screen.blit(text, (width/4+8,height-height/4-10))
pygame.display.update()
pygame.image.save(newscreen, 'background.png')
pygame.image.save(text, 'starttext.png')

# i button
pygame.draw.rect(newscreen, (255,0,120), pygame.Rect(width - 50, 10, 40,40))
screen.blit(newscreen,(0,0))
pygame.display.update()
myFont = pygame.font.SysFont("Times New Roman", 25)
ibutton = myFont.render("i", False, (0, 0, 0))
screen.blit(ibutton, (width-32,17))
pygame.display.update()

# Mouse click
while True:
    left,right,center = pygame.mouse.get_pressed()
    if left == True:
        if event.type == MOUSEBUTTONUP:
            x,y = pygame.mouse.get_pos()
            if ((width/4) <= x <= ((width/4) + (width/2))) and ((height-height/4) <= y <= ((height-height/4) + height/76)):
                #move to next screen
                break

time.sleep(5)

这与链接问题不同，因为我的程序是针对GUI的，并且需要鼠标单击事件。

Answer 1

Ted Klein Bergamn的这个答案解释了窗口为什么没有响应的原因：https://stackoverflow.com/a/42719689/6220679

应使用pygame.event.get：

running = True
while running:
    for event in pygame.event.get():
        # This lets you quit by pressing the X button of the window.
        if event.type == pygame.QUIT:
            running = False
        elif event.type == pygame.MOUSEBUTTONUP:
            if event.button == 1:  # 1 = left mouse button, 2 = middle, 3 = right.
                print('mouse up')
                x,y = pygame.mouse.get_pos()
                if ((width/4) <= x <= ((width/4) + (width/2))) and ((height-height/4) <= y <= ((height-height/4) + height/76)):
                    #move to next screen
                    running = False

对于您的情况（对于简单的GUI应用程序），pygame.event.wait可能是一个不错的选择（它使程序在队列中没有任何事件时可以进入睡眠状态）。

running = True
while running:
    event = pygame.event.wait()
    if event.type == pygame.MOUSEBUTTONUP:
        if event.button == 1:
            print('mouse up')
            x,y = pygame.mouse.get_pos()
            if ((width/4) <= x <= ((width/4) + (width/2))) and ((height-height/4) <= y <= ((height-height/4) + height/76)):
                #move to next screen
                running = False

Pygame窗口运行良好，直到单击为止，然后显示“无响应”

1 个答案: