Question

我想将第2列中的缺失值填充到相应的col1中。

import pandas as pd
data={"col1":["A","B","C","A","B","C","A","B","A"], "col2":["{hey1}"," ","{hello2}","{hey2}","{he1}","{hello3}","set()","set()","{hey1}"]}
df=pd.DataFrame(data=data)

它应该用一些规则填充，如下所示：例如，如果A出现四次且在4中出现，则它具有对应的col2值三次，而第四个缺失。因此缺失值应该是这三者的结合。像在这种情况下一样，3个值分别为hey1，hey2，hey1。第四失踪应该包含hey2，hey1。 Set（）是垃圾值，我不需要该值。因此，在处理列比较之前，我想将其删除。所需的输出：

col1 col2
A     hey1
B    he1
C    hello2
A    hey2
B    he1
C     hello3
A    hey1,hey2
B    he1
A    hey1

Answer 1

data = {"col1": ["A", "B", "C", "A", "B", "C", "A", "B", "A"],
        "col2": ["", " ", "hello2", "hey2", "he1", "hello3", " ", "", ""]}
col1 = data["col1"]
col2 = data["col2"]

d = collections.defaultdict(list)
new_col2 = []
for i, tup in enumerate(list(zip(col1, col2))):
    key, value = tup
    if not value.strip():
        new_val = ", ".join(d[key])
        if not new_val:
            if len(new_col2) >= 1:
                new_val = new_col2[i - 1]
            else:
                new_val = ""

        new_col2.append(new_val)
    else:
        d[key].append(value)
        new_col2.append(value)

如何基于列比较Python填充缺失值

1 个答案: