Question

这里是详细信息

TBL1

rec_id,    rec_amount,       rec_date

1            1500             1/1/2011  
2            4500             1/1/2011  
3            500             1/1/2011  
4            15000             1/1/2011  
5            7500             1/1/2011

TBL2

vouc_id       vouc_amount        pay_date
1             15000              1/1/2011
2              750.50            1/1/2011
3              560                1/1/2011

TBL3

don_id      d_amount           d_date
1           1500                1/1/2011
2             2000              1/1/2011

我在单个查询sum(rec_amount) from tbl1中需要sum(vouc_amount) from tbl2和sum(d_amount) from tbl3以及where date = 1/1/2011。任何身体可以帮助我吗？

Answer 1

在表之间使用union all并在

之上执行SUM

例如

SELECT SUM(TheAmount)
FROM(
SELECT rec_amount AS TheAmount
FROM tbl1
WHERE  rec_date = '20110101'
UNION ALL
SELECT vouc_amount        
FROM tbl2
WHERE  pay_date = '20110101'
UNION ALL
SELECT d_amount           
FROM tbl3
WHERE  d_date = '20110101') x

或彼此相邻

SELECT SUM(rec_amount) AS tbl1Amount,(SELECT SUM(vouc_amount)   
FROM tbl2
WHERE  pay_date = '20110101') AS tbl2Amount ,(SELECT SUM(d_amount)          
FROM tbl3
WHERE  d_date = '20110101')  AS tbl3Amount  
FROM tbl1
WHERE  rec_date = '20110101'

Answer 2

您可以为每列进行子选择。

declare @T1 table(rec_id int, rec_amount int, rec_date datetime)
declare @T2 table(vouc_id int, vouc_amount int, pay_date datetime)
declare @T3 table(don_id int, d_amount int, d_date datetime)

insert into @T1 values 
(1, 1500 , '2011-01-01'),
(2, 4500 , '2011-01-01'),
(3, 500  , '2011-01-01'),
(4, 15000, '2011-01-01'),
(5, 7500 , '2011-01-01')


insert into @T2 values
(1, 15000, '2011-01-01'),
(2, 750  , '2011-01-01'),
(3, 560  , '2011-01-01')

insert into @T3 values
(1, 1500, '2011-01-01'),
(2, 2000, '2011-01-01')


select
(select sum(rec_amount)
 from @T1
 where rec_date = '2011-01-01'),
(select sum(vouc_amount)
 from @T2
 where pay_date = '2011-01-01'),
(select sum(d_amount)
 from @T3
 where d_date = '2011-01-01')

SQL Server在单个查询中从多个表中求和

2 个答案: