Question

我已经使用python连接到SQL Server来执行查询。我有一个显示以下示例的当前列表：

[('TEST', 'dbo', 'XXX', 'Practice', 1, 'char', 3, 3, None, None, 1, None, None, 1, None, 3, 1, 'YES', 39)
('TEST', 'dbo', 'XXX', 'ParPracticeCode', 1, 'char', 3, 3, None, None, 1, None, None, 1, None, 3, 2, 'YES', 39)
('TEST', 'dbo', 'XXX', 'PracOnlyName', 12, 'varchar', 100, 100, None, None, 1, None, None, 12, None, 100, 3, 'YES', 39)]

但是，我想拆分列表并通过仅包含第四个项目（例如Practice，ParPracticeCode和PracOnlyName）来创建新列表。变成new_list = [Practice, ParPracticeCode, PracOnlyName]

Answer 1

sample = [('TEST', 'dbo', 'XXX', 'Practice', 1, 'char', 3, 3, None, None, 1, None, None, 1, None, 3, 1, 'YES', 39), ('TEST', 'dbo', 'XXX', 'ParPracticeCode', 1, 'char', 3, 3, None, None, 1, None, None, 1, None, 3, 2, 'YES', 39), ('TEST', 'dbo', 'XXX', 'PracOnlyName', 12, 'varchar', 100, 100, None, None, 1, None, None, 12, None, 100, 3, 'YES', 39)]
new_list = [x[3] for x in sample]

Answer 2

x = [('TEST', 'dbo', 'XXX', 'Practice', 1, 'char', 3, 3, None, None, 1, None, None, 1, None, 3, 1, 'YES', 39),
     ('TEST', 'dbo', 'XXX', 'ParPracticeCode', 1, 'char', 3, 3, None, None, 1, None, None, 1, None, 3, 2, 'YES', 39),
     ('TEST', 'dbo', 'XXX', 'PracOnlyName', 12, 'varchar', 100, 100, None, None, 1, None, None, 12, None, 100, 3, 'YES', 39)]

编写一个for循环，以像二维矩阵一样访问列表中每个元素的值“ 4”

new_list = []

for i in range(len(x)):
    new_list.append(x[i][3])

此实现将完成

Python列表拆分，仅提取某些项目以创建新列表

2 个答案: