我有一个列表,其中包含165个电影标题和信息(来自json文件):
results =
['tt0758758',
'Into the Wild',
'2007',
'Emile Hirsch',
' Marcia Gay Harden',
' William Hurt',
' Jena Malone',
'',
'Based on a true story. After graduating from Emory University',
' Christopher McCandless abandoned his possessions',
' gave his entire savings account to charity',
' and hitchhiked to Alaska to live in the wilderness. Along the way',
' Christopher encounters a series of characters who shape his life.',
'Sean Penn',
'8.1',
'516',
'973']
我只想存储选定的值
tt0758758 Into the Wild , ['Sean Penn', '8.1', '516', '973']
到另一个列表results_add= []
。
请注意,条目的元素大小不同。
我尝试过:
results_add = []
for i in range(len(results)-1):
results_add = (results[i+1][0],results[i+1][1],results[i+1][-4:])
print(results_add)
这会打印整个列表,但只会将最后一个值(标题)存储到我新创建的列表中
len(results_add)
3
答案 0 :(得分:1)
您要追加到results_add
列表中。正如您当前的代码一样,它只会在每次迭代后覆盖:
results_add = []
for i in range(len(results)-1):
temp = (results[i+1][0],results[i+1][1],results[i+1][-4:])
results_add.append(temp)
print(results_add)
答案 1 :(得分:0)
for i in range(len(results)-1):
results_add = (results[i+1][0],results[i+1][1],results[i+1][-4:])
每次循环,您都要重新分配results_add
,它会丢失其先前的内容。