Question

entity seguidor is
    port(
        clk, sensorIzq, sensorDer, sensorDisp : in std_logic;
        llantaIzq, llantaDer, disp: out std_logic);
end;

architecture comportamiento of seguidor is

begin

    movimiento: process (sensorIzq, sensorDer, sensorDisp,clk)
     begin
        if(sensorIzq='1' and sensorDer='0' and sensorDisp = '0') then
            llantaIzq<='1';
            llantaDer<='0';
        elsif(sensorIzq='0' and sensorDer='1'and sensorDisp = '0') then
            llantaIzq<='0';
            llantaDer<='1';
        elsif(sensorIzq = '1' and sensorDer = '1' and sensorDisp = '0') then
            llantaIzq <= '1';
            llantaDer <= '1';
        elsif(sensorIzq = '1' and sensorDer = '1' and sensorDisp = '1') then
            llantaIzq <= '0';
            llantaDer <= '0';

        end if;
    end process movimiento;
    end comportamiento;

因此，代码适用于行跟随者，如果它读取＆＃39; 1＆＃39;从其中一个传感器，它应该通过＆＃39; 1＆＃39; （即5v。）其中一个轮子。阅读＆＃39; 1＆＃39;来自＆＃34; sensorDisp＆＃34;，汽车应停一会儿，给出＃34; disp＆＃34;价值为＆＃39; 1＆＃39;在此期间。在那之后，它应该继续它的快乐方式。我很难尝试实现这种延迟。谢谢你的帮助！

Answer 1

我在Atlys做过类似的事情。有clk counter.Know .ucf文件（映射文件）中的时钟频率。有等待状态的布尔值，isWait。当sensorDisp为1时，则isWait = true 我在下面提到了伪代码。

您可以使用输入clk和sensordisp为此创建单独的进程。并且记住，如果在任何代码运行中没有为任何变量/信号分配任何值，如果将推断锁存器，因为它需要先前的值，因为它未被分配。

movimiento: process (clk,sensorIzq, sensorDer, sensorDisp,clk)
     begin
     if(clk edge ) then 
        if (isWait) then 
            if(wait_counter < "frequency")) then 
              wait_couter++;
             else 
              isWait = False;
              Disp = '0';
            end if;
        else 
          if(sensorDisp = '1') then 
             wait_counter = 0;
             isWait = True;
              Disp <= '1';
          end if;

          if(sensorIzq='1' and sensorDer='0' and sensorDisp = '0') then
              llantaIzq<='1';
              llantaDer<='0';
          elsif(sensorIzq='0' and sensorDer='1'and sensorDisp = '0') then
              llantaIzq<='0';
              llantaDer<='1';
          elsif(sensorIzq = '1' and sensorDer = '1' and sensorDisp = '0') then
              llantaIzq <= '1';
              llantaDer <= '1';
          elsif(sensorIzq = '1' and sensorDer = '1' and sensorDisp = '1') then
              llantaIzq <= '0';
              llantaDer <= '0';
          end if;
      end if;
    end if;
    end process movimiento;
    end comportamiento;

VHDL如何在一段时间后将输出从1切换到0？

1 个答案: