Question

我有数据框，如下面的示例数据。我正在尝试将数据帧中的一行转换为dict，如下面所需的输出。但是当我使用to_dict时，我得到了indice和列值。有谁知道如何将行转换为dict，如所需的输出？任何提示非常感谢。

Sample data:

print(catStr_df[['Bottle Volume (ml)', 'Pack']][:5])

      Bottle Volume (ml)  Pack
595                  750    12
1889                 750    12
3616                1000    12
4422                 750    12
5022                 750    12


Code:

v = catStr_df[catStr_df['Item Number']==34881][['Bottle Volume (ml)', 'Pack']]\
.drop_duplicates(keep='first').to_dict()

v

Output:

{'Bottle Volume (ml)': {9534: 1000}, 'Pack': {9534: 12}}

Desired output:

{'Bottle Volume (ml)': 1000, 'Pack': 12}

Answer 1

尝试将.to_dict('records')[0]添加到您想要的行

catStr_df[catStr_df['Item Number']==34881].to_dict('records')[0]

Answer 2

采用不同的策略，这可行，但您需要获取列列表。这假设您希望索引号作为字典项

def row_converter(row, listy):
    #convert pandas row to a dictionary
    #requires a list of columns and a row as a tuple
    count = 1
    pictionary = {}
    pictionary['Index'] = row[0]
    for item in listy:
        pictionary[item] = row[count]
        count += 1
    print(pictionary)
    return pictionary

df = PD.read_csv("yourFile", dtype=object, delimiter=",", na_filter=False)
listy = df.columns
for row in df.itertuples():
    rowDict = row_converter(row, listy)

将数据帧行转换为dict

2 个答案: