Question

我已经宣布了这样的活动

class QuestionnaireActivity<T : ProfileModel> : AppCompatActivity()

我想写一个espresso测试，所以我写了像ActivityTestRule

@Rule @JvmField
val activityRule = object : ActivityTestRule<QuestionnaireActivity<ProfileModel.PersonalInfo>>(QuestionnaireActivity<ProfileModel.LifeStyleInfo>::class.java){
    override fun getActivityIntent(): Intent = QuestionnaireActivity.getQuestionnaireIntent(InstrumentationRegistry.getTargetContext(), 3, ProfileModel.LifeStyleInfo())
}

但是编译器抱怨（它关于ActivityTestRule的参数）

only classes are allowed on the left hand side of a class literal

说明here仿制药不能与 class 一起使用。

如果删除泛型类型参数，则错误变为

 Type inference failed.
 Expected type mismatch: inferred type is Class<QuestionnaireActivity<*>> but Class<QuestionnaireActivity<ProfileModel.PersonalInfo>!>! was expected

我该怎么办？

感谢您的关注

Answer 1

类似于here，解决方案涉及定义像这样的内联函数

inline fun <reified T: Activity> activityTestRuleWithIntent(intent: Intent) =  object : ActivityTestRule<T>(T::class.java){
    override fun getActivityIntent(): Intent = intent
}

然后规则变为：

@Rule @JvmField
val rule = activityTestRuleWithIntent<QuestionnaireActivity<ProfileModel.LifeStyleInfo>>(QuestionnaireActivity.getQuestionnaireIntent(InstrumentationRegistry.getTargetContext(), 3, ProfileModel.LifeStyleInfo()))

espresso ActivityTestRule用于具有泛型类型参数的活动

1 个答案: