MySql部分总和

Question

我需要帮助来总结代码相同的每个值，这是我的数据

OFFICECODE | DATE | VAL
10200 | 2018-05-01 | 1
10200 | 2018-05-02 | 2
10100 | 2018-05-01 | 3
10100 | 2018-05-02 | 2

我想得到这个结果

OFFICECODE | DATE | SUM(VAL) 
10200 | 2018-05-01 | 1
10200 | 2018-05-02 | 3 (1+2)
10100 | 2018-05-01 | 3
10100 | 2018-05-02 | 5 (3+2)

我尝试此查询，但结果总和所有OFFICECODE

SELECT
      A.OFFICELKD,
      A.DATE,
      A.VAL,
      @VAL := @VAL + A.VAL AS `VALSUM`
   FROM 
      ( SELECT
              cur.OFFICELKD,
              cur.DATE,
              cur.VAL
           FROM
              tblReport cur
           LEFT JOIN 
          tblReport pre
       ON cur.OFFICECODE = pre.OFFICECODE
       GROUP BY cur.ID
           ORDER BY
              OFFICECODE ) AS A,
      ( SELECT @VAL := 0 ) AS SqlA
   ORDER BY OFFICECODE, DATE

请帮我解决这个问题

Answer 1

你很亲密。您需要考虑OFFICECODE：

SELECT r.*,
       (@val := if(@o = r.OFFICECODE, @val + a.val,
                   if(@o := r.OFFICECODE, a.val, a.val)
                  )
       ) as valsum
FROM (SELECT r.*
      FROM tblReport r 
      ORDER BY OFFICECODE, DATE
     ) r CROSS JOIN
     ( SELECT @o := -1, @VAL := 0 ) params;