Question

我是Lua的新手，所以请耐心地跟我说话。我在Lua中有2个csv字符串

a= '1,2,3,4,5'

代表索引和

b='this,needs,to,be,matched:with,every,single,row,here:'

行由＆＃39;：＆＃39;分隔。字符而不是换行符

预期输出

1,this,2,needs,3,to,4,be,5,matched
1,with,2,every,3,single,4,row,5,here

我尝试使用以下代码单独迭代它们

local result= {}
local u = unpack or table.unpack
for values in string.gmatch(values_csv, '([^:]+)') do
    local data = {}
    for column1,column2 in string.gmatch(values, '([^,]+)'),string.gmatch(keys, '([^,]+)') do
        print(column1, column2)
    end
end

由于某种原因，第二个总是零。我无法在没有外部库的Lua中找到类似于Python的zip函数。我如何同时迭代这两个。谢谢你的帮助

Answer 1

Egor的解决方案的变体，以便按照您的要求获得输出：

a = '1,2,3,4,5'
b = 'this,needs,to,be,matched:with,every,single,row,here:'

for line in b:gmatch '[^:]+' do
  local idx = a:gmatch '%d+'
  local ans = {}
  for v in line:gmatch '[^,]+' do
    ans[#ans+1] = idx()
    ans[#ans+1] = v
  end
  print(table.concat(ans,','))
end

Answer 2

local keys = '1,2,3,4,5'
local values_csv = 'this,needs,to,be,matched:with,every,single,row,here:some,values,,are,absent:'

for values in values_csv:gmatch'[^:]+' do
   local data = {}
   local keys_iter = keys:gmatch'[^,]+'
   for value_column in (values..','):gmatch'([^,]*),' do
      print(keys_iter(), value_column)
   end
end

如何在没有外部库的情况下在Lua中实现此循环

2 个答案: