我有一个Register
函数,它以std::function<void(const uint8_t* data, size_t len)>
为参数。我想使用对象的成员函数作为目标。
我发现this question根据其答案是使用std::bind
将第一个第一个参数(隐式this
指针)绑定到实际的对象指针,然后将其用作std::function
论证。
然而,这在C ++ 11,C ++ 14和C ++ 17中都不再起作用了吗?
考虑以下测试程序。
#include <iostream>
#include <cstdint>
#include <functional>
void Register(std::function<void(const uint8_t* data, size_t len)> func) {
//Dummy - directly call into function
func(nullptr, 0);
}
class TestClass {
public:
void TestRegister() {
Register(
std::bind(&TestClass::TestTarget, this, std::placeholders::_1)
);
}
void TestTarget(const uint8_t* data, size_t len) {
(void) data;
(void) len;
std::cout << "Hello there" << std::endl;
}
};
int main() {
TestClass testObj;
testObj.TestRegister();
return 0;
}
在为-std=c++17
进行编译时,会抛出一条相当神秘的错误消息(我不知道它在Wrong number of arguments for pointer-to-member
处要说的是什么):
In file included from /home/max/Documents/TestingFunctions/main.cpp:3:0:
/usr/include/c++/7/functional: In instantiation of ‘struct std::_Bind_check_arity<void (TestClass::*)(const unsigned char*, long unsigned int), TestClass*, const std::_Placeholder<1>&>’:
/usr/include/c++/7/functional:854:12: required from ‘struct std::_Bind_helper<false, void (TestClass::*)(const unsigned char*, long unsigned int), TestClass*, const std::_Placeholder<1>&>’
/usr/include/c++/7/functional:875:5: required by substitution of ‘template<class _Func, class ... _BoundArgs> typename std::_Bind_helper<std::__is_socketlike<_Func>::value, _Func, _BoundArgs ...>::type std::bind(_Func&&, _BoundArgs&& ...) [with _Func = void (TestClass::*)(const unsigned char*, long unsigned int); _BoundArgs = {TestClass*, const std::_Placeholder<1>&}]’
/home/max/Documents/TestingFunctions/main.cpp:14:78: required from here
/usr/include/c++/7/functional:841:7: error: static assertion failed: Wrong number of arguments for pointer-to-member
static_assert(_Varargs::value
^~~~~~~~~~~~~
/home/max/Documents/TestingFunctions/main.cpp: In member function ‘void TestClass::TestRegister()’:
/home/max/Documents/TestingFunctions/main.cpp:14:26: error: could not convert ‘std::bind(_Func&&, _BoundArgs&& ...) [with _Func = void (TestClass::*)(const unsigned char*, long unsigned int); _BoundArgs = {TestClass*, const std::_Placeholder<1>&}; typename std::_Bind_helper<std::__is_socketlike<_Func>::value, _Func, _BoundArgs ...>::type = std::_Bind<void (TestClass::*(TestClass*, std::_Placeholder<1>))(const unsigned char*, long unsigned int)>](((TestClass*)this), std::placeholders::_1)’ from ‘std::_Bind_helper<false, void (TestClass::*)(const unsigned char*, long unsigned int), TestClass*, const std::_Placeholder<1>&>::type {aka std::_Bind<void (TestClass::*(TestClass*, std::_Placeholder<1>))(const unsigned char*, long unsigned int)>}’ to ‘std::function<void(const unsigned char*, long unsigned int)>’
std::bind(&TestClass::TestTarget, this, std::placeholders::_1)
~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
将TestRegister
函数替换为在lambda表达式中完全相同的函数编译并运行没有问题。
void TestRegister() {
Register(
[this](const uint8_t* data, size_t len) {
TestTarget(data, len);
}
);
}
问题:为什么来自链接问题的std::bind
方法不起作用?是否删除了此功能或我的代码中是否有错误?
答案 0 :(得分:4)
您的函数Register
需要一个带有两个参数的函数,但是您尝试将一个带有一个placeholded参数的函数传递给它。
void TestRegister() {
Register(
std::bind(&TestClass::TestTarget, this, std::placeholders::_1, std::placeholders::_2)
);
}
答案 1 :(得分:2)
您的函数有两个参数,而您只传递一个占位符。
std::bind(&TestClass::TestTarget, this, std::placeholders::_1, std::placeholders::_2);