我必须实现Rational
类才能获得Rational分数。 header.h
文件由我的导师提供,因此我必须跟进。我还必须在Rational::Rational(const Rational& cRational)
函数中编写复制构造函数,以便可以复制object
。我编写了我的代码,但在输出中添加分数是错误的。任何人都可以帮我解决这个问题吗?我的编码在Rational::addition(const Rational &a)
中有什么问题或者我该如何解决?
输出:
Begin Rational Class Tests
Testing default constructor: 1/1
Testing std constructor: 1/2
Testing copy constructor: 1/2
Testing addition: 4/4 + 1/2 = 4/4 // it should be 1/2 + 1/2 = 4/4
主要功能:
int main()
{
cout << "Begin Rational Class Tests\n\n";
cout<<"Testing default constructor: ";
Rational n1;
n1.printRational();
cout << endl << endl;
cout<<"Testing std constructor: ";
Rational n2(1,2);
n2.printRational();
cout << endl << endl;
cout<<"Testing copy constructor: ";
Rational n3(n2);
n3.printRational();
cout << endl << endl;
cout<<"Testing addition: ";
n1 = n2.addition(n3);
n2.printRational();
cout <<" + ";
n3.printRational();
cout <<" = ";
n1.printRational();
cout << endl << endl;
}
标题文件:
class Rational {
public:
Rational(); // default constructor
Rational(int, int); //std (initialisation) constructor
Rational(const Rational&); //copy constructor
Rational addition(const Rational &);
void printRational();
private:
int numerator;
int denominator;
};
我的节目:
//default constructor
Rational::Rational()
{
numerator = 1;
denominator = 1;
}
//initialize constructor
Rational::Rational(int n, int d)
{
numerator = n;
if (d==0)
{
cout << "ERROR: ATTEMPTING TO DIVIDE BY ZERO" << endl;
exit(0); // will terminate the program if division by 0 is attempted
}
else
denominator = d;
}
//copy constructor
Rational::Rational(const Rational& cRational)
{
numerator = cRational.numerator;
denominator = cRational.denominator;
}
//addition
Rational Rational::addition(const Rational &a)
{
numerator = numerator * a.denominator + a.numerator * denominator;
denominator = denominator * a.denominator;
return Rational(numerator,denominator);
}
void Rational::printRational()
{
cout << numerator << "/" << denominator ;
}
答案 0 :(得分:1)
除了()之外,只需为分子和分母的新值创建具有不同名称的新变量,就像这样......
int n, d; //you could use better names
n = numerator * a.denominator + a.numerator * denominator;
d = denominator * a.denominator;
return Rational(n, d);
我查了一下,这有效here。
一般情况下,不要在同一范围内对两个变量使用相同的名称。
答案 1 :(得分:1)
你的添加功能正在修改*this
的成员变量,这会导致奇怪的事情发生
Rational addition(const Rational &) const;
因为这会让编译器告诉你,你正在做一些奇怪的事情。
您可以使用局部变量而不是分配给成员,也可以完全不使用中间变量:
Rational Rational::addition(const Rational &a)
{
return Rational(numerator * a.denominator + a.numerator * denominator,
denominator * a.denominator);
}