Question

嘿伙计们开始我会说我在发布这个问题之前已经研究了很多类似的程序，但仍需要一些帮助。我的问题在于加法分数类函数，我需要将一个分数添加到另一个分数。我有一个类，目前正在处理该类的实例（fractionObject和fractionObject2）。我分别存储我的分数，一个在fractionObject中，一个在fractionObject2中。如何在我的分数类功能中添加这些功能＆＃39;添加＆＃39;？

任何提示将不胜感激！谢谢你的时间！

#include <iostream>
#include <string>
#include <sstream>
using namespace std;

// Regular prototypes
int stringToNumber(const string &Text);
int GCD(int, int);
int LCM(int, int);

class fraction{

public: // Access Specifier
    int numerator;
    int  denominator; // Can never be 0



    // Function Prototypes
    fraction();
    void setNumDen();
    void reduce();
    void add();


};

// Member functions definitions
fraction::fraction()
{
    numerator = 0;
    denominator = 0;
}

void fraction::setNumDen()
{
    string numString;
    string denString;
    do{
        cout << "Enter a numerator and denominator of fraction 1 separated by whitespace: ";
        getline(cin, numString, ' ');
        getline(cin, denString);
        if (denString == "0")
            cout << endl << "Please enter a number that isn't zero." << endl;
    } while (denString == "0"); // Making sure denominator is not zero

    numerator = stringToNumber(numString);
    denominator = stringToNumber(denString);

}

void fraction::reduce()
{
    int leastCommonMultiple = 0;

    leastCommonMultiple = LCM(numerator, denominator);

    numerator /= leastCommonMultiple;
    denominator /= leastCommonMultiple;
}

void fraction::add()
{
    int leastComDen;

}

int main()
{

    fraction fractionObject, fractionObject2;

    fractionObject.setNumDen();
    fractionObject2.setNumDen();
    // Reducing and displaying the reduced fractions
    fractionObject.reduce();
    fractionObject2.reduce();
    cout << "Reduced Fraction 1 = " << fractionObject.numerator << "/" << fractionObject.denominator << "\t" << "Reduced Fraction 2 = " << fractionObject2.numerator << "/" << fractionObject2.denominator << endl;
    // Adding and displaying the fractions



    system("pause");
    return 0;
}

// Function to convert string to number
int stringToNumber(const string &Text)//Text not by const reference so that the function can be used with a 
{                               //character array as argument
    stringstream ss(Text);
    int result;
    return ss >> result ? result : 0;
}

// result=GCD(a,b)
int LCM(int a, int b) {
    int temp = 0;

    while (b != 0) {
        temp = b;
        b = a%b;
        a = temp;
    }
    return a;
}

// result=LCM(a,b);
int GCD(int a, int b) {
    int result = 0;

    result = a * (b / LCM(a, b));
    return result;
}

Answer 1

这里没有完整的答案，但是add应该有两个const fraction&参数并返回一个临时的fraction对象。您可以将其重命名为operator+。许多库添加了一个+=运算符，不需要创建临时对象。 C ++ 11允许您使用移动构造函数来减少这些临时对象的开销。

至于实施，这里有一个提示：1/6 + 1/9 =（9 + 6）/ 54 = 5/18。我注意到你已经有了reduce函数。

添加分数和类 - Woot

1 个答案: