如何根据另一个字段的特定值排除字段中具有特定值的行?深入探讨:
我有一个名为" rule_name"的列这是从案例陈述中得出的。
我有另一个名为" DeliveryTermsIdentifier"那是从另一张桌子拉出来的(见下面查询结果的图片)。
我尝试删除带有rule_name "需要传递事件" 的行,仅当 DeliveryTermsIdentifier为" PP" ," DA"等。我被抛弃了,因为我的rule_name列已基于条件了。
以下是用于派生这两列的SQL:
,case when s.ShipmentNo is not null then cast(dqr.rulename as varchar(30))
else cast(dqc.dataqualityruleid as varchar(30)) end as rule_name
,case when (dqd.SuccessFlag = 0) then 'Missing'
when (dqd.SuccessFlag = 1) then 'Reported'
when (s.ShipmentNo is null) then 'Missing' end reporting_result
,s.DeliveryTermsIdentifier
from CustomerMasterList cml
join organization o on o.organizationid = cml.senderid
inner join DataQualityConfig dqc on dqc.DomainId = cml.DomainID
left outer join shipment s on s.shipmentno = cml.shipmentno
left outer join dataqualityresult dqd on dqd.shipmentid = s.shipmentid
left outer join dataqualityrule dqr on dqr.dataqualityruleid
=dqd.dataqualityruleid
答案 0 :(得分:0)
一种方法是将您拥有的内容放在子查询中,并使用外部查询中的where子句过滤掉。 E.g。
0000-00d0: xx xx xx xx xx xx xx xx-ff c4 00 1f-00 00 01 05 !....... ........
0000-00e0: 01 01 01 01-01 01 00 00-00 00 00 00-00 00 01 02 ........ ........
0000-00f0: 03 04 05 06-07 08 09 0a-0b ff c4 00-b5 10 00 02 ........ ........
0000-0100: 01 03 03 02-04 03 05 05-04 04 00 00-01 7d 01 02 ........ .....}..
0000-0110: 03 00 04 11-05 12 21 31-41 06 13 51-61 07 22 71 ......!1 A..Qa."q
0000-0120: 14 32 81 91-a1 08 23 42-b1 c1 15 52-d1 f0 24 33 .2....#B ...R..$3
0000-0130: 62 72 82 09-0a 16 17 18-19 1a 25 26-27 28 29 2a br...... ..%&'()*
0000-0140: 34 35 36 37-38 39 3a 43-44 45 46 47-48 49 4a 53 456789:C DEFGHIJS
0000-0150: 54 55 56 57-58 59 5a 63-64 65 66 67-68 69 6a 73 TUVWXYZc defghijs
0000-0160: 74 75 76 77-78 79 7a 83-84 85 86 87-88 89 8a 92 tuvwxyz. ........
0000-0170: 93 94 95 96-97 98 99 9a-a2 a3 a4 a5-a6 a7 a8 a9 ........ ........
0000-0180: aa b2 b3 b4-b5 b6 b7 b8-b9 ba c2 c3-c4 c5 c6 c7 ........ ........
0000-0190: c8 c9 ca d2-d3 d4 d5 d6-d7 d8 d9 da-e1 e2 e3 e4 ........ ........
0000-01a0: e5 e6 e7 e8-e9 ea f1 f2-f3 f4 f5 f6-f7 f8 f9 fa ........ ........
0000-01b0: ff c4 00 1f-01 00 03 01-01 01 01 01-01 01 01 01 ........ ........
0000-01c0: 00 00 00 00-00 00 01 02-03 04 05 06-07 08 09 0a ........ ........
0000-01d0: 0b ff c4 00-b5 11 00 02-01 02 04 04-03 04 07 05 ........ ........
0000-01e0: 04 04 00 01-02 77 00 01-02 03 11 04-05 21 31 06 .....w.. .....!1.
0000-01f0: 12 41 51 07-61 71 13 22-32 81 08 14-42 91 a1 b1 .AQ.aq." 2...B...
0000-0200: c1 09 23 33-52 f0 15 62-72 d1 0a 16-24 34 e1 25 ..#3R..b r...$4.%
0000-0210: f1 17 18 19-1a 26 27 28-29 2a 35 36-37 38 39 3a .....&'( )*56789:
0000-0220: 43 44 45 46-47 48 49 4a-53 54 55 56-57 58 59 5a CDEFGHIJ STUVWXYZ
0000-0230: 63 64 65 66-67 68 69 6a-73 74 75 76-77 78 79 7a cdefghij stuvwxyz
0000-0240: 82 83 84 85-86 87 88 89-8a 92 93 94-95 96 97 98 ........ ........
0000-0250: 99 9a a2 a3-a4 a5 a6 a7-a8 a9 aa b2-b3 b4 b5 b6 ........ ........
0000-0260: b7 b8 b9 ba-c2 c3 c4 c5-c6 c7 c8 c9-ca d2 d3 d4 ........ ........
0000-0270: d5 d6 d7 d8-d9 da e2 e3-e4 e5 e6 e7-e8 e9 ea f2 ........ ........
0000-0280: f3 f4 f5 f6-f7 f8 f9 fa-xx xx xx xx xx xx xx xx ........ .....(..
答案 1 :(得分:0)
您还可以将case语句封装到外部apply中,并使用如下别名:
SELECT * ,
rules.rule_name ,
RESULT.reporting_result ,
s.DeliveryTermsIdentifier
FROM CustomerMasterList cml
JOIN organization o ON o.organizationid = cml.senderid
INNER JOIN DataQualityConfig dqc ON dqc.DomainId = cml.DomainID
LEFT OUTER JOIN shipment s ON s.shipmentno = cml.shipmentno
LEFT OUTER JOIN dataqualityresult dqd ON dqd.shipmentid = s.shipmentid
LEFT OUTER JOIN dataqualityrule dqr ON dqr.dataqualityruleid = dqd.dataqualityruleid
OUTER APPLY ( SELECT CASE WHEN ( dqd.SuccessFlag = 0 ) THEN 'Missing'
WHEN ( dqd.SuccessFlag = 1 ) THEN 'Reported'
WHEN ( s.ShipmentNo IS NULL ) THEN 'Missing'
END reporting_result ) RESULT
OUTER APPLY ( SELECT CASE WHEN s.ShipmentNo IS NOT NULL THEN
CAST(dqr.rulename AS VARCHAR(30))
ELSE
CAST(dqc.dataqualityruleid AS VARCHAR(30))
END AS rule_name ) rules
WHERE s.DeliveryTermsIdentifier NOT IN ( 'PP', 'DA' )
AND rules.rule_name <> 'Delivery event required';