Question

我试图删除列B中所有行的值，其中列B =＆＃39; S＆＃39;。这是我可以用数据显示的一个例子：

    column A    column B
    100         S
    100         P
    100         C
    101         P
    101         C
    102         S
    103         C
    104         P

从这里开始，我要删除A列中显示＆＃39; S＆＃39;的所有条目。在B栏（100和102）中，我留下了：

column A    column B
    101         P
    101         C
    103         C
    104         P

我试图按照类似的SO帖子（Exclude rows with a column containing a value if multiple rows exist for）中的步骤进行操作，但它仍然排除了＆＃39; S＆＃39;存在并保持共享列A值。

例如，我在查询的相关部分是：

select table_a.column_a
    ,table_b.column_b
    ,...
from table_z
inner join table_b
    on table_z.z = table_b.z
inner join table_y
    on table_z.y = table_y.y
left outer join table_a
    on table_x.x = table_a.x
where date > 'YYYY-MM-DD'
    and (
        table_b.column_b not in (
            select column_b
            from table_b
            where (column_b = 'S')
            )
        )
order by table_a.column_a

但它只删除了column_b =＆＃39; S＆＃39;并且不会删除column_A值与column_b出现位置匹配的行（本帖子开头的column_a = 100示例）。

Answer 1

Declare @YourTable table (ColumnA int,ColumnB varchar(25))
Insert Into @YourTable values
(100,'S'),
(100,'P'),
(100,'C'),
(101,'P'),
(101,'C'),
(102,'S'),
(103,'C'),
(104,'P')

Select * 
 From  @YourTable
 Where ColumnA Not In (Select Distinct ColumnA From @YourTable where ColumnB='S')

返回

ColumnA ColumnB
101     P
101     C
103     C
104     P

Answer 2

我认为您需要在where子句中的子查询中使用Table_A而不是Table_B：

    select *
from Table_A
where Column_B != 'S'
    and Column_A not in (
        select distinct column_A
        from Table_A
        where Column_B = 'S'
        )

修改了您的查询。这应该有效：

select table_a.column_a
    ,table_b.column_b
    ,...
from table_z
inner join table_b
    on table_z.z = table_b.z
inner join table_y
    on table_z.y = table_y.y
left outer join table_a
    on table_x.x = table_a.x
where date > 'YYYY-MM-DD'
    and table_a.column_b != 'S'
    and table_a.column_A not in (
        select distinct table_a.column_A
        from Table_A
        where Column_B = 'S'
        )
order by table_a.column_a

Answer 3

SELECT *
FROM   Table_A as A
WHERE  NOT EXISTS (
  SELECT *
  FROM   Table_B as B
  WHERE  B.ColumnA = A.ColumnA
  AND    B.ColumnB = 'S' )

这与另一个答案非常相似，只是它使用NOT EXISTS而不是NOT IN。 IN关键字非常有用，但出于可能的性能原因using NOT IN should be avoided。

Answer 4

SELECT *
  FROM YourTable
 WHERE column_A IN ( SELECT column_A FROM YourTable
                     EXCEPT
                     SELECT column_A FROM YourTable 
                      WHERE column_B = 'S' );

根据列值从查询结果中排除行

4 个答案: