我有2个形状矩阵：
pob.shape = (2,49,20)
rob.shape = np.zeros((2,49,20))
我希望获得pob元素的索引值！= 0。所以在numpy我能做到这一点：
x,y,z = np.where(pob!=0)
例如：
x = [2,4,7]
y = [3,5,5]
z = [3,5,6]
我想更改rob的值：
rob[x1,y1,:] = np.ones((20))
我如何使用tensorflow对象执行此操作？ 我试图使用tf.where但我无法从张量obj中获取索引值
答案 0 :(得分：0)
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</div> </body> </html>创建索引矩阵，然后根据条件使用tf.range()来获取满足它的索引。然而，接下来会出现棘手的部分：您无法根据TF（tf.meshgrid()）中的索引轻松地将值分配给张量。
针对您的问题的解决方法（＆＃34;对于所有tf.where()，如果my_tensor[my_indices] = my_values然后(i,j,k)＆＃34;）可以如下：
pob[i,j,k] != 0