Question

我不知道为什么，但这让我感到震惊。

我的代码：

    import random

    game()

        def game ():
        p_choice = raw_input("What do you choose?")
        cpu_random = random.randint(1,3)
        cpu_choice = cpu_random
        if cpu_random == 1:
            cpu_choice = "Rock"
        elif cpu_random == 2:
            cpu_choice = "Paper"
        elif cpu_random == 3:
            cpu_choice = "Scissors"




    if cpu_choice == p_choice:
        print ("Tie!")


    if p_choice == "Rock" and cpu_choice == "Paper":
        print ('''Uh Oh. You lost 
        Try Again next time!''')
        play_again = raw_input ("Would you like to play again?")
    if p_choice == "Rock" and cpu_choice == "Scissors":
        print ("You Win!!!")
        play_again = raw_input ("Would you like to play again?")

    if p_choice == "Paper" and cpu_choice == "Rock":
        print ("You Win!!!")
        play_again = raw_input ("Would you like to play again?")
    if p_choice == "Paper" and cpu_choice == "Scissors":
        print ('''Uh Oh. You lost 
        Try Again next time!''')
        play_again = raw_input ("Would you like to play again?")

    if p_choice == "Scissors" and cpu_choice == "Rock":
        print ('''Uh Oh. You lost 
        Try Again next time!''')
        play_again = raw_input ("Would you like to play again?")
    if p_choice == "Scissors" and cpu_choice == "Paper":
        print ("You Win!!!")
        play_again = raw_input ("Would you like to play again?")

def play_again ():
    if play_again == "Yes" or "yes":
        game()
    if play_again == "No" or "no":
        print ("Okay. See you next time")
        exit()

我问它时插入这个：

Rock

然后我得到一个如下所示的错误代码：

NameError: name 'Rock' is not defined

如果这是重复的话，提前抱歉，但无论如何，谢谢。我在其上找不到任何其他东西。

可能有用的东西：

我正在使用一个名为spyder2的程序来编码。如果你知道plz的帮助。

编辑：

错误的完整命令行：

runfile('/home/ubuntu-meyer9095/rockpaperscissors.py', wdir='/home/ubuntu-meyer9095')

What do you choose?Rock
Traceback (most recent call last):

  File "<ipython-input-7-d0814fe6acfd>", line 1, in <module>
    runfile('/home/ubuntu-meyer9095/rockpaperscissors.py', wdir='/home/ubuntu-meyer9095')

  File "/usr/lib/python2.7/dist-packages/spyderlib/widgets/externalshell/sitecustomize.py", line 699, in runfile
    execfile(filename, namespace)

  File "/usr/lib/python2.7/dist-packages/spyderlib/widgets/externalshell/sitecustomize.py", line 81, in execfile
    builtins.execfile(filename, *where)

  File "/home/ubuntu-meyer9095/rockpaperscissors.py", line 6, in <module>
    game()

  File "/home/ubuntu-meyer9095/rockpaperscissors.py", line 9, in game
    p_choice = raw_input("What do you choose?")

  File "/usr/lib/python2.7/dist-packages/IPython/kernel/zmq/ipkernel.py", line 364, in <lambda>
    input = lambda prompt='': eval(raw_input(prompt))

  File "<string>", line 1, in <module>

NameError: name 'Rock' is not defined

Answer 1

在python 3.x中，“raw_input”函数已经过时，最好只使用“input（）”，然后在定义它之前调用“game（）”函数，因此代码不知道要找什么。第三，Play_Again（）函数永远不会被使用，因为你没有像使用“game（）”那样调用它。我建议您完全重构代码并查看有关函数Functions的本教程。很酷的项目！

（空白）未在我的Rock Paper Scissors Program

1 个答案: