Question

问题：程序似乎不接受输入的整数。不会添加赢/输/抽奖计数，也不会在调试模式下显示计算机选择

该计划的基础设计： 编写一个程序，让用户可以在计算机上玩Rock，Paper，Scissors游戏。该计划应如下工作。显示一个菜单：

得分：0胜0平0负（D）ebug显示计算机的选择（新游戏（Q）UIT

如果用户输入“Q”或“q”，程序将结束。对于新游戏，“N”或“n”，对于调试模式，“D”或“d”，其他任何内容都会导致显示错误消息。

当游戏开始时，生成1到3范围内的随机数。如果数字是1，那么计算机选择了摇滚。如果数字是2，则计算机选择了纸张。如果数字是3，那么计算机选择了剪刀。（除非我们处于“D”ebug模式，否则不要显示计算机的选择。）
用户在键盘上输入他选择的“1-rock”，“2-paper”或“3-scissors”。
显示计算机的选择。
根据以下规则选择获胜者： •如果一个玩家选择摇滚而另一个玩家选择剪刀，则摇滚获胜。（岩石砸碎了剪刀。） •如果一个玩家选择剪刀而另一个玩家选择纸张，那么剪刀就会赢。（剪刀剪纸。） •如果一个玩家选择纸张而另一个玩家选择摇滚，则纸张获胜。（纸包裹着岩石。） •如果两个玩家做出相同的选择，那么游戏就是平局。
您的计划将保持赢，输和抽奖的总数。
重新显示菜单并重复游戏循环。

我的计划：

import random

def main():

    continuing = "y"

    win = 0
    lose = 0
    draw = 0

    while continuing == "y":
        print("Score:", win,"wins,", draw, "draws,", lose,"losses")
        print("(D)ebug to show computer's choice")
        print("(N)ew game")
        print("(Q)uit")

        choice = input(" ")

        if choice == "n" or choice == "N":
            win, draw, lose = playgame(win, draw, lose)

        elif choice == "d" or choice == "D":
            win, draw, lose = playgame2(win, draw, lose)

        elif choice == "q" or choice == "Q":
            break


def playgame(win, draw, lose):

    computer = random.randint(1,3)
    player = input("Enter 1 for Rock, 2 for Paper, or 3 for Scissors: ")

    if computer == 1 and player == 2:
        Score = "You won"
        win += 1

    elif computer == 1 and player == 3:
        Score = "You lost"
        lose += 1

    elif computer == 2 and player == 1:
        Score = "You lost"
        lose += 1

    elif computer == 2 and player == 3:
        Score = "You won"
        win += 1

    elif computer == 3 and player == 1:
        Score = "You won"
        win += 1

    elif computer == 3 and player == 2:
        Score = "You lost"
        lose += 1

    elif computer == player:
        Score = "Draw"
        draw += 1

    return (win, draw, lose)

def playgame2(win, draw, lose):

    computer = random.randint(1, 3)
    player = input("Enter 1 for Rock, 2 for Paper, or 3 for Scissors: ")

    if computer == 1 and player == 2:
        Score = "You won"
        print("Computer chose rock")
        win += 1

    elif computer == 1 and player == 3:
        Score = "You lost"
        print("Computer chose rock")
        lose += 1

    elif computer == 2 and player == 1:
        Score = "You lost"
        print("Computer chose paper")
        lose += 1

    elif computer == 2 and player == 3:
        Score = "You won"
        print("Computer chose paper")
        win += 1

    elif computer == 3 and player == 1:
        Score = "You won"
        print("Computer chose scissors")
        win += 1

    elif computer == 3 and player == 2:
        Score = "You lost"
        print("Computer chose scissors")
        lose += 1

    elif computer == player:
        Score = "Draw"
        print("Computer chose the same as you")
        draw += 1

    return (win, draw, lose)


main()

Answer 1

我不是Pythonista，但是在猜测input returns strings，你需要在与计算机的int进行比较之前转换为整数。

我还认为你错过了DRYing up你的代码中的一个技巧 - 你应该能够有一个playgame方法，它需要一个额外的布尔参数debugmode，而不是直接调用print，调用间接，例如：

def debugPrint(debugString, debugMode)
     if debugMode
         print(debugString)

希望这有道理吗？

Answer 2

这将在Python 2.x中工作，但在Python 3.x中不行在Python 3.x中，input（）返回字符串。因此，玩家的输入将具有“ 1”或“ 2”或“ 3”的形式。由于1和“ 1”不同，因此该程序将不会执行playgame（）和playgame2（）中if和elif块中的任何行。这是一个Python 3.x示例：

>>> a = input("Input = ")
Input = 1
>>> print a
SyntaxError: Missing parentheses in call to 'print'
>>> print(a)
1
>>> a
'1'
>>> type(a)
<class 'str'>

因此，无论何时要输入整数，都应使用i = int（input（“ Input =”）））。

但是，在Python 2.x中，input（）本身将1设为1，而不是1。但是，当您想将字符串输入为inpu时，还必须加上引号。这是一个例子：

>>> a1 = input("Input = ")
Input = 1
>>> a1
1
>>> type(a1)
<type 'int'>
>>> #I want to input a string now:
>>> a2 = input("Input = ")
Input = string

Traceback (most recent call last):
  File "<pyshell#12>", line 1, in <module>
    a2 = input("Input = ")
  File "<string>", line 1, in <module>
NameError: name 'string' is not defined
>>> a2 = input("Input = ")
Input = "string"
>>> a2
'string'
>>> type(a2)
<type 'str'>
>>> a3 = raw_input("Input = ")
Input = hello
>>> a3
'hello'
>>> type(a3)
<type 'str'>
>>>

在Python 2.x中，raw_input（）函数将输入作为字符串。

Rock Paper Scissors程序不起作用（Python）

2 个答案: