如何从构造的VertexArray中绘制我选择的原语?在下面的例子中,我将两个顶点添加到'vertices'数组,我试图用'window.draw(vertices,2,sf :: Lines)'绘制它,但它给了我一个错误。我知道我可以使用'sf :: Vertex foo [] = {..}'创建线对象,但我希望能够将顶点附加到数组而不是一次初始化所有内容。
#include <SFML/Window.hpp>
#include <SFML/OpenGL.hpp>
#include <SFML/Graphics.hpp>
#include <iostream>
int main()
{
// Create the main window
sf::RenderWindow window(sf::VideoMode(640, 480), "SFML");
sf::Clock clock;
sf::VertexArray vertices;
sf::Vertex vertex;
vertex.position = sf::Vector2f(0, 0);
vertex.color = sf::Color(100, 0, 200);
vertices.append(vertex);
vertex.position = sf::Vector2f(100, 100);
vertex.color = sf::Color(100, 0, 200);
vertices.append(vertex);
// Start the game loop
bool running = true;
while (running)
{
// Process events
sf::Event event;
while (window.pollEvent(event))
{
// Close window: exit
if (event.type == sf::Event::Closed)
running = false;
}
window.clear(sf::Color::Black);
window.draw(vertices,2 ,sf::Lines);
window.display();
}
return 0;
}
答案 0 :(得分:1)
您可以在声明vertices.setPrimitiveType(sf::Lines);
后致电sf::VertexArray vertices;
,然后绘制它:window.draw(vertices);
或者您可以在构造函数中设置其基本类型以及点数,然后您可以使用operator[]
访问这些点:
sf::VertexArray line(sf::Lines, 2); //or sf::LineStrip
line[0].position = sf::Vector2f(0, 0);
line[0].color = sf::Color(100, 0, 200);
line[1].position = sf::Vector2f(100, 100);
line[1].color = sf::Color(100, 0, 200);
...
window.draw(line);
参考:enum sf::PrimitiveType,sf::VertexArray,VertexArray tutorial