Question

我需要找到n = 20的因子，我的代码如下所示。

int n=20;
for (int i = 1; i <= n; i++) {
        if(n%i==0){
            System.out.println(i+" ,");

        }
       }

它产生结果1,2,4,5,10,20

但是我能找到每个相邻数字的区别吗？像1-2 = -1， 2-4 = -2 ......

Answer 1

    /* package whatever; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Ideone
{
    public static void main (String[] args) throws java.lang.Exception
    {
        int n=20;
        int a = 0;
        int b = 0;
        for (int i = 1; i <= n; i++) {
         if(n%i==0){
         b = i;
         if(a!=0)
                    System.out.println(a - b+" ,");
         a = i;

            }
       }
    }

这将打印出您想要的内容。

Answer 2

继续将最后一个因子保存在变量中，并在获得下一个因子时将其减去。

    int n = 20;
    //1 is the factor of every no.
    //So let's assign 1 to the first variable
    int last = 1;

    for(int i=2; i<=n; i++) {
        if(n%i==0) {
            //i is the factor of n:
            System.out.print((i-last) + " ");
            //Save the this factor to use next:
            last = i;
        }
    }

如何使用单个循环获得元素的差异？

2 个答案: