Question

我连接到Web服务并下拉JSON对象。

我的班级

public class UserLogin implements Serializable
{
    public int objMobileCapabilityId;
    public int objMobileCapabilityValue;
    public String objMobileCapabilityDesc;
    public int objMobileDisplayOrder;

    public UserLogin(){}

    public UserLogin(int objmobilecapabilityid, int objmobilecapabilityvalue, String objmobilecapabilitydesc, int objmobiledisplayorder) {

        objMobileCapabilityId = objmobilecapabilityid;
        objMobileCapabilityValue = objmobilecapabilityvalue;
        objMobileCapabilityDesc = objmobilecapabilitydesc;
        objMobileDisplayOrder = objmobiledisplayorder;
    }
}

然后，我使用TAGS

获取该数据并创建UserLogin arraylist

ArrayList<UserLogin> listofCapabilities = new ArrayList<UserLogin>();
try {
   // Invole web service
   androidHttpTransport.call(NAMESPACE+METHOD_NAME, envelope);
   // Get the response

        SoapPrimitive response = (SoapPrimitive) envelope.getResponse();
        String responseJSON=response.toString();
        JSONArray jarray =new JSONArray(responseJSON);

        ACount = (jarray.length() -1);
        for (int i = 0; i <= ACount; i++) {

          Description = jarray.getJSONObject(i).getString(TAG_Description);
            if(Description.equals("Not a Valid Mobile User")){
                userOK = false;
            }else {
                userOK = true;
                objuserlogin.setProperty(2, Description);
                listofCapabilities.add(i, objuserlogin);
                objuserlogin = new UserLogin();
            }
        }

    } catch (Exception e) {
        e.printStackTrace();
    }

然后我将ArrayList传递给第二个Activity

protected void onPostExecute(Void result) {
    Log.i(TAG, "onPostExecute");
    if (userOK == true){
        Intent DisplayValidList = new Intent(MainActivity.this,  DisplayValidList.class);
        DisplayValidList.putExtra("Capabilities", listofCapabilities);
           startActivity(DisplayValidList);
    }else {
        Toast.makeText(MainActivity.this,
                            "You have entered an invalid User Name or Password. Please try again.", Toast.LENGTH_LONG).show();
    }

}

这是我在第二项活动中获得的内容

ArrayList userCapabilities;
userCapabilities = getIntent().getStringArrayListExtra("Capabilities");

userCapabilities = {ArrayList@4448}  size = 2
 0 = {UserLogin@4458} 
  objMobileCapabilityDesc = "Test Rick"
  objMobileCapabilityId = 0
  objMobileCapabilityValue = 0
  objMobileDisplayOrder = 0
  shadow$_klass_ = {Class@4033} "class   rick.damselfly.com.traceall_mobile_app.UserLogin"
  shadow$_monitor_ = -1993118517
 1 = {UserLogin@4459} 
  objMobileCapabilityDesc = "Receive RM (Add/Edit/Delete)"
  objMobileCapabilityId = 0
  objMobileCapabilityValue = 0
  objMobileDisplayOrder = 0
  shadow$_klass_ = {Class@4033} "class rick.damselfly.com.traceall_mobile_app.UserLogin"
  shadow$_monitor_ = -2045944664

很抱歉代码的数量，不知道描述我想要做的最好的方法。我做错了什么？

Answer 1

好吧，基本上你没有正确地创建你的对象。请看下面的内容。

首先是你的班级。除非您以不同的方式定义变量，否则您将无法检索这些值。为了使示例更容易，我只是在您的值中添加了一些getter。

public class UserLogin {

public int objMobileCapabilityId;
public int objMobileCapabilityValue;
public String objMobileCapabilityDesc;
public int objMobileDisplayOrder;

public UserLogin(){}

public UserLogin(int objmobilecapabilityid, int objmobilecapabilityvalue, String objmobilecapabilitydesc, int objmobiledisplayorder) {

    objMobileCapabilityId = objmobilecapabilityid;
    objMobileCapabilityValue = objmobilecapabilityvalue;
    objMobileCapabilityDesc = objmobilecapabilitydesc;
    objMobileDisplayOrder = objmobiledisplayorder;
}

public int getObjMobileCapabilityId() {
    return objMobileCapabilityId;
}

public int getObjMobileCapabilityValue() {
    return objMobileCapabilityValue;
}

public String getObjMobileCapabilityDesc() {
    return objMobileCapabilityDesc;
}

public int getObjMobileDisplayOrder() {
    return objMobileDisplayOrder;
}
}

接下来，可能更大的问题是您检索和解析JSON以创建新用户对象的方式。下面你可以看到我是如何做到这一点的。基本上你可以创建JSON数组，然后在for循环中创建单独的JSONObject，然后可以访问它们来创建UserLogin对象。另外你会看到我创建了一个String来保存JSON，这只是你的响应字符串（我这样做是为了便于测试）。

private void readYourJSON(){
    String jsonString = "[{\"objMobileCapabilityId\":2,\"objMobileCapabilityValue\":2,\"objMobileCapabilityDe\":\"Test Rick\",\"objMobileDisplayOrder\":2},{\"objMobileCapabilityId\":1,\"objMobileCapability\":1,\"objMobileCapabilityDesc\":\"Receive RM (Add\\/Edit\\/Delete)\",\"objMobileDisplayOrder\":1}]";
    ArrayList<UserLogin> users = new ArrayList<>();
    try {
        JSONArray array = new JSONArray(jsonString);
        Log.e("Size: ", String.valueOf(array.length()));
        for(int i = 0; i < array.length(); i++){
            JSONObject currentObject = (JSONObject) array.get(i);
            users.add(new UserLogin(currentObject.getInt("objMobileCapabilityId"),
                    currentObject.getInt("objMobileCapabilityValue"),
                    currentObject.getString("objMobileCapabilityDe"),
                    currentObject.getInt("objMobileDisplayOrder")
                    ));
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }
    txt.setText(users.get(0).getObjMobileCapabilityDesc());
}

现在您可以忽略底部的txt.setText，这样我就可以向您展示更改的最终结果。我将JSON解析卡入了一个小方法，所以这很明显这是出于示例目的，您需要根据自己的需要进行定制。另外，我强烈建议您查看下面发布的资源，以帮助您快速了解此类内容。

最终结果示例

<强>资源

JSON - http://www.androidhive.info/2012/01/android-json-parsing-tutorial/

对象：http://mrbool.com/how-to-create-objects-in-android/27048

如何使用For循环获取objMobileCapabilityDesc的字符串值？

1 个答案: