r中文本的时间序列分析

Question

如果我有这样的数据：

df = data.frame(person = c('jim','john','pam','jim'),
                date =c('2018-01-01','2018-02-01','2018-03-01','2018-04-01'),
                text = c('the lonely engineer','tax season is upon us, engineers, do your taxes!','i am so lonely','rage coding is the best')                  )

我希望按日期了解趋势条款，我该怎么办呢？

  xCorp = corpus(df, text_field = 'text')
    x = tokens(xCorp) %>% tokens_remove(
      c(
        stopwords('english'),
        'western digital',
        'wd',
        'nil'),
      padding = T
    ) %>%
      dfm(
        remove_numbers = TRUE,
        remove_punct = TRUE,

        remove_symbols = T,
        concatenator = ' '
      )
  x2 = dfm(x, groups = 'date') 

这会让我成为那里的一部分，但不确定它是不是最好的方式。

Answer 1

使用tidyverse，我能够做到以下几点：

 df = df %>% 
        group_by(date) %>%
        unnest_tokens(word,text) %>%
        count(word,sort = T) %>%  
    }