r中非线性PCA的自举特征值

时间:2018-04-12 11:29:57

标签: r pca bootstrapping eigenvalue

我在r中运行非线性PCA,使用homals包。以下是我使用的一大块代码:

res1 <- homals(data = mydata, rank = 1, ndim = 9, level = "nominal")
res1 <- rescale(res1)

我想在此分析中生成1000个特征值的bootstrap估计值(替换),但我无法弄清楚代码。有没有人有任何建议?

示例数据:

dput(head(mydata, 30))

structure(list(`W age` = c(45L, 43L, 42L, 36L, 19L, 38L, 21L, 
27L, 45L, 38L, 42L, 44L, 42L, 38L, 26L, 48L, 39L, 37L, 39L, 26L, 
24L, 46L, 39L, 48L, 40L, 38L, 29L, 24L, 43L, 31L), `W education` = c(1L, 
2L, 3L, 3L, 4L, 2L, 3L, 2L, 1L, 1L, 1L, 4L, 2L, 3L, 2L, 1L, 2L, 
2L, 2L, 3L, 3L, 4L, 4L, 4L, 2L, 4L, 4L, 4L, 1L, 3L), `H education` = c(3L, 
3L, 2L, 3L, 4L, 3L, 3L, 3L, 1L, 3L, 4L, 4L, 4L, 4L, 4L, 1L, 2L, 
2L, 1L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 2L, 4L), `N children` = c(10L, 
7L, 9L, 8L, 0L, 6L, 1L, 3L, 8L, 2L, 4L, 1L, 1L, 2L, 0L, 7L, 6L, 
8L, 5L, 1L, 0L, 1L, 1L, 5L, 8L, 1L, 0L, 0L, 8L, 2L), `W religion` = c(1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), `W employment` = c(1L, 
1L, 1L, 1L, 1L, 1L, 0L, 1L, 1L, 0L, 1L, 0L, 0L, 1L, 1L, 1L, 1L, 
1L, 1L, 0L, 0L, 1L, 1L, 1L, 1L, 0L, 0L, 0L, 1L, 1L), `H occupation` = c(3L, 
3L, 3L, 3L, 3L, 3L, 3L, 3L, 2L, 3L, 1L, 1L, 3L, 2L, 4L, 2L, 2L, 
2L, 2L, 4L, 3L, 1L, 1L, 1L, 3L, 1L, 1L, 2L, 2L, 1L), `Standard of living` = 
c(4L, 
4L, 3L, 2L, 3L, 2L, 2L, 4L, 2L, 3L, 3L, 4L, 3L, 3L, 1L, 4L, 4L, 
3L, 1L, 1L, 1L, 4L, 4L, 4L, 3L, 4L, 4L, 2L, 4L, 4L), Media = c(0L, 
0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), Contraceptive = c(1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L)), .Names = c("W age", 
"W education", "H education", "N children", "W religion", "W employment", 
"H occupation", "Standard of living", "Media", "Contraceptive"
), row.names = c(NA, 30L), class = "data.frame")
> 

我获得了resmals功能,可以与homals包一起使用,以实现最佳缩放。这是功能:

rescale <- function(res) {
    # Rescale homals results to proper scaling
    n <- nrow(res$objscores)
    m <- length(res$catscores)
    res$objscores <- (n * m)^0.5 * res$objscores
    res$scoremat <- (n * m)^0.5 * res$scoremat
    res$catscores <- lapply(res$catscores, FUN = function(x) (n * m)^0.5 * x)
    res$cat.centroids <- lapply(res$cat.centroids, FUN = function(x) (n * m)^0.5 * x)
    res$low.rank <- lapply(res$low.rank, FUN = function(x) n^0.5 * x)
    res$loadings <- lapply(res$loadings, FUN = function(x) m^0.5 * x)
    res$discrim <- lapply(res$discrim, FUN = function(x) (n * m)^0.5 * x)
    res$eigenvalues <- n * res$eigenvalues
    return(res)
}

1 个答案:

答案 0 :(得分:0)

在R中引导的标准方法是使用基础包boot 我对后面的代码并不是很满意,因为它会抛出很多警告。但也许这是由于我测试过的数据集。我在help("homals")中使用了数据集和第3个示例。

我只运行了10次bootstrap重复。

library(homals)
library(boot)

boot_eigen <- function(data, indices){
    d <- data[indices, ]
    res <- homals(d, active = c(rep(TRUE, 4), FALSE), sets = list(c(1,3,4),2,5))
    res$eigenvalues
}

data(galo)

set.seed(7578)    # Make the results reproducible
eig <- boot(galo, boot_eigen, R = 10)

eig
#
#ORDINARY NONPARAMETRIC BOOTSTRAP
#
#
#Call:
#boot(data = galo, statistic = boot_eigen, R = 10)
#
#
#Bootstrap Statistics :
#     original      bias    std. error
#t1* 0.1874958  0.03547116 0.005511776
#t2* 0.2210821 -0.02478596 0.005741331

colMeans(eig$t)
#[1] 0.2229669 0.1962961

如果在您的情况下也无法正常运行,请说明,我将删除答案。

编辑。

为了回答评论中的讨论,我更改了函数boot_eigen,现在对homals的调用遵循问题代码,并在返回之前调用rescale。 / p>

boot_eigen <- function(data, indices){
    d <- data[indices, ]
    res <- homals(data = d, rank = 1, ndim = 9, level = "nominal")
    res <- rescale(res)
    res$eigenvalues
}

set.seed(7578)    # Make the results reproducible
eig <- boot(mydata, boot_eigen, R = 10)