我不知道为什么。我正在用json将mousemove和mousedown coordiantes发送到服务器,它返回我发送的相同jsons坐标...我认为问题是当我收到响应时,画布没有正确绘制。
这是我的画布代码:
$(document).ready(() => {
console.log("THE DOC IS READY :)");
drawing();
connect();
});
var start = {};
var draw = {};
var close = {};
var myCanvas;
var ctx;
var dimensionProps;
function drawing() {
myCanvas = document.getElementById("canvas");
ctx = myCanvas.getContext("2d");
setProps(myCanvas, 800, 500);
dimensionProps = {
left: myCanvas.offsetLeft,
top: myCanvas.offsetTop
};
if (myCanvas) {
let mouseisDown = false;
var cPosX, cPosY;
ctx.lineWidth = 5;
$(myCanvas).mousedown((e) => {
mouseisDown = true;
start.x = e.pageX;
start.y = e.pageY;
console.log("start"+JSON.stringify(start))
sendDraw(start);
//startDraw(start.x,start.y)
}).mousemove((e) => {
if (mouseisDown) {
draw.x = e.pageX;
draw.y = e.pageY;
console.log("drawing"+JSON.stringify(draw))
sendDraw(draw);
//drawingCanvas(draw.x,draw.y)
}
}).mouseup((e) => {
mouseisDown = false;
});
}
clear(ctx, myCanvas);
}
const setProps = (canvas, w, h) => {
canvas.width = w;
canvas.height = h;
}
const clear = (ctx, canvas) => {
$("#clear-btn").click(() => {
ctx.clearRect(0, 0, canvas.width, canvas.height);
});
}
// cross-browser canvas coordinates
const drawingPos = (pPos, dProps) => ((pPos) - (dProps));
这就是websocket(我收到java后端的坐标是“onmessage”):
var ws;
const sendDraw = (coord) => ws.send(JSON.stringify(coord));
const close = () => ws.close;
function connect() {
ws = new WebSocket("ws://" + location.host + "/Board_Project/chatsv");
ws.onmessage = (e) => {
var mydraw = JSON.parse(e.data);
console.log("this is what i received " + JSON.stringify(mydraw)); //the same coordiantes that I send
startDraw(mydraw.x,mydraw.y);
drawingCanvas(mydraw.x, mydraw.y);
//endDraw();
}
ws.onopen = (e) => {
console.log("SUCCESSFULLY CONNECTION");
}
ws.onclose = (e) => {
if (ws.readyState === WebSocket.OPEN) {
console.log("THE CONNECTION HAS FINISHED");
}
}
ws.onerror = (e) => {
console.log("error al conectar");
}
}
const startDraw = (x, y) => {
ctx.beginPath();
ctx.strokeStyle = "black";
cPosX = x - dimensionProps.left;
cPosY = y - dimensionProps.top;
//ctx.moveTo(x,y); //it works
ctx.moveTo(cPosX,cPosY);
}
const drawingCanvas = (x, y) => {
cPosX = x - dimensionProps.left;
cPosY = y - dimensionProps.top;
ctx.lineTo(cPosX+10,cPosY+10);
ctx.stroke();
}
const endDraw = () => ctx.closePath();
我不发布java服务器的代码,因为它只获取json,然后再次发送。所以我认为发布它不是必要的。
希望你能帮助我!
谢谢!
答案 0 :(得分:0)
你说“服务器只能获取json,然后再发送它。”
嗯,关键是你需要在ws.onmessage时让mousemove与mousedown不同。
你的webSocket无法分辨出mousedown和mousemove的区别。 mousedown和mousemove侦听器都调用sendDraw()。
$(myCanvas).mousedown((e) => {
mouseisDown = true;
/* ...*/
sendDraw(start);
//startDraw(start.x,start.y)
}).mousemove((e) => {
if (mouseisDown) {
/* ...*/
sendDraw(draw);
//drawingCanvas(draw.x,draw.y)
}
})
当您的webSocket从服务器获取消息时,它将始终调用startDraw()和drawingCanvas()。
无论是通过mousemove还是mousedown触发它。
ws.onmessage = (e) => {
var mydraw = JSON.parse(e.data);
console.log("this is what i received " + JSON.stringify(mydraw)); //the same coordiantes that I send
startDraw(mydraw.x,mydraw.y);
drawingCanvas(mydraw.x, mydraw.y);
//endDraw();
}
因此,您可以使用ws.onmessage的mouseisDown或在调用sendDraw时添加一些标记。
ws.onmessage = (e) => {
var mydraw = JSON.parse(e.data);
if(mouseisDown){
drawingCanvas(mydraw.x, mydraw.y);
} else {
startDraw(mydraw.x,mydraw.y);
}
//endDraw();
}