Question

我对sed / bash有点新意，我试图从这个地址中提取url（基本上是.com的/ .infos / xyz）基本上抓住“”中的域并输出到新文件中

来源：

(window,arguments);})(2,340000,625803,"domain.com",7,3,0,1200,"anotherdomain.info",0,[],1,[],[],false,"sdfs-fdsf",0 "remove_file_ext":true,"mode":"sector","sector":".dlitre"},"domain.xyz",5,0.4,0.8,[],0,"//vghvghv.

期望的输出：

domain.com
anotherdomain.info
domain.xyz

Answer 1

您能否请关注awk并告诉我这是否对您有所帮助。

awk '{while(match($0,/"[^"]*/)){val=substr($0,RSTART+1,RLENGTH-1);if(val ~ /com|info|xyz/){print val};$0=substr($0,RSTART+RLENGTH+1)}}' Input_file

现在也添加非单线形式的解决方案。

awk '
{
  while(match($0,/"[^"]*/)){
     val=substr($0,RSTART+1,RLENGTH-1);
     if(val ~ /com|info|xyz/){ print val };
     $0=substr($0,RSTART+RLENGTH+1)}
}
'  Input_file

从字符串中提取URL的地址

1 个答案: