Question

我们如何使用PHP识别字符串中的URL并将它们存储在数组中？

如果网址包含逗号，则无法使用explode函数，它不会给出正确的结果。

Answer 1

REGEX是您的问题的答案。采用对象操纵器的答案......所有它缺失的是排除＆＃34;逗号＆＃34;，所以你可以尝试这个排除它们的代码并给出3个独立的URL作为输出：

$string = "The text you want to filter goes here. http://google.com, https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/";

preg_match_all('#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#', $string, $match);

echo "<pre>";
print_r($match[0]); 
echo "</pre>";

，输出

Array
(
    [0] => http://google.com
    [1] => https://www.youtube.com/watch?v=K_m7NEDMrV0
    [2] => https://instagram.com/hellow/
)

Answer 2

请尝试使用以下正则表达式

$regex = '/https?\:\/\/[^\",]+/i';
preg_match_all($regex, $string, $matches);
echo "<pre>";
print_r($matches[0]);

希望这对你有用

Answer 3

您可以在此处试用Regex：

$string = "The text you want to filter goes here. http://google.com, https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/";

preg_match_all('#\bhttps?://[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/))#', $string, $match);

echo "<pre>";
print_r($match[0]); 
echo "</pre>";

这给出了以下输出：

Array
(
  [0] => http://google.com
  [1] => https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/
)

Answer 4

$urlstring = "The text you want to filter goes here. http://google.com, https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/";

preg_match_all('#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#', $urlstring , $result);

print_r($result[0]);

Answer 5

试试这个

function getUrls($string)
{
$regex = '/https?\:\/\/[^\" ]+/i';
preg_match_all($regex, $string, $matches);
return ($matches[0]);
}
$urls = getUrls($string);
print_r($urls);

或

$str = '<a href="http://foobar.com"> | Hello world Im a http://google.fr |     Did you mean:http://google.fr/index.php?id=1&b=6#2310';
$pattern = '`.*?((http|ftp)://[\w#$&+,\/:;=?@.-]+)[^\w#$&+,\/:;=?@.-]*?`i';
if (preg_match_all($pattern,$str,$matches)) 
{
print_r($matches[1]);
}

它会起作用

Answer 6

$string = "The text you want to filter goes here. http://google.com,
https://www.youtube.com/watch?v=K_m7NEDMrV0,https://instagram.com/hellow/";

preg_match_all('#\bhttps?://[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/))#',
$string, $match);

echo "<pre>"; $arr = explode(",", $match[0][1]);
print_r($match[0][0]); print_r($arr); echo "</pre>";

使用PHP从字符串中提取URL

6 个答案: