Question

Sample Output

我需要为每个人更新一个具有相同编号的SSN字段。因为它们无效而无论哪个SSN都无关紧要，只需要它们用于SSN格式的唯一标识符。这意味着最小或最大数量是可以接受的。当前表包括可以按多列分组的行，以确保每个人都是唯一的，例如名字，姓氏，地址和患者编号。

我如何获取John Doe的EmpID1值并将其复制到每一行，然后对Jane Doe的多行执行相同操作？

谢谢！

Answer 1

因为它只需要是“SSN格式”，所以我们可以使用row_number。此外，您的问题是矛盾的，因为您声明需要格式的唯一标识符，但也声明需要为每个人更新具有相同编号的SSN字段这意味着相同SSN适合所有人。以下解决方案基于您提供的预期输出。这比交换记录容易。

create table #testTable (EmpID1 varchar(11) null, LastName2 char(3), FirstName3 char(4))
insert into #testTable
values
(null,'DOE','JOHN'),
(null,'DOE','JOHN'),
(null,'DOE','JOHN'),
(null,'DOE','JOHN'),
(null,'DOE','JOHN'),
(null,'DOE','JOHN')


;with cte as
(select 
    RN = row_number() over (order by (select null)) + 111111111
    , * 
 from #testTable)

update cte
set EmpID1 = stuff(stuff(RN,4,0,'-'),7,0,'-')

select * from #testTable

drop table #testTable

<强>返回

+-------------+-----------+------------+
|   EmpID1    | LastName2 | FirstName3 |
+-------------+-----------+------------+
| 111-11-1112 | DOE       | JOHN       |
| 111-11-1113 | DOE       | JOHN       |
| 111-11-1114 | DOE       | JOHN       |
| 111-11-1115 | DOE       | JOHN       |
| 111-11-1116 | DOE       | JOHN       |
| 111-11-1117 | DOE       | JOHN       |
+-------------+-----------+------------+

Answer 2

您可以尝试以下查询语句。

DECLARE @EmployeeTable TABLE(EmpID1 VARCHAR(20),FirstName VARCHAR(100),LastName VARCHAR(100),PatientNumber INT)
INSERT INTO @EmployeeTable
SELECT '970-42-3783','John','Doe',1 UNION ALL SELECT '971-42-3780','John','Doe',1 UNION ALL SELECT '973-42-4081','John','Doe',1

SELECT * FROM @EmployeeTable

DECLARE @FirstName AS VARCHAR(100)
DECLARE @LastName AS VARCHAR(100)
DECLARE @PatientNumber INT
DECLARE @EmpID1 AS VARCHAR(20)

DECLARE EmployeeCursor CURSOR FOR
    SELECT A.FirstName,A.LastName,A.PatientNumber FROM
    (SELECT COUNT(*) AS NoOfRow,FirstName,LastName,PatientNumber FROM @EmployeeTable
    GROUP BY FirstName,LastName,PatientNumber) A
OPEN EmployeeCursor
    FETCH NEXT FROM EmployeeCursor into @FirstName,@LastName,@PatientNumber

    WHILE ( @@FETCH_STATUS = 0)
    BEGIN
        SET @EmpID1 = (SELECT TOP 1 EmpID1 FROM  @EmployeeTable WHERE FirstName = @FirstName AND LastName = @LastName AND PatientNumber = @PatientNumber)

        UPDATE @EmployeeTable SET EmpID1 = @EmpID1
        WHERE FirstName = @FirstName AND LastName = @LastName AND PatientNumber = @PatientNumber

        FETCH NEXT FROM EmployeeCursor into @FirstName,@LastName,@PatientNumber
    END

    CLOSE EmployeeCursor
    DEALLOCATE EmployeeCursor

    SELECT * FROM @EmployeeTable

以前的数据

EmpID1          FirstName   LastName    PatientNumber
970-42-3783     John        Doe             1
971-42-3780     John        Doe             1
973-42-4081     John        Doe             1

更新后

EmpID1          FirstName   LastName    PatientNumber
970-42-3783     John        Doe             1
970-42-3783     John        Doe             1
970-42-3783     John        Doe             1

更新按名称分组的行的单个字段

2 个答案: